尝试将此代码与以下代码绑定以创建进入程序的密码的困境

Question

代码：

print(Fore.CYAN +'Welcome To Manifest by Jysko#0420!')
print(Fore.LIGHTMAGENTA_EX, end='')
tools = '''Tools: 
webchecker
portscanner
webhook spammer'''
print(Fore.LIGHTYELLOW_EX, end='')
print('TOOLS ARE CASE SENSITIVE!')
print(Fore.LIGHTMAGENTA_EX, end='')
print(tools)

secret_word = 'Blaze4'
guess = ''
print(Fore.YELLOW, end='')
guess = input('Enter Password: ')
try:
  if guess != secret_word:
    print(Fore.RED, end='')
    error = print('ACCESS DENIED')
  else:
    print(Fore.GREEN, end='')
    print('ACCESS GRANTED')
except:
  print('')
#NEW CODE IS ABOVE!
def funt():
  print(Fore.GREEN, end='')
  tool = input('Enter Desired Tool: ')
  print('')
  if tool == 'webchecker':
      try:
        print(Fore.CYAN, end='')
        site = input('Please Enter The Website Here: ')
        response = requests.get(site)
        requests.get(site)
        if response.status_code == 200:
          print('')
          print(f'{Fore.GREEN}Online!')
          sleep(1)
        else:
          print(f'{Fore.RED}Offline!')
          sleep(1)
      except:
        print('') 
  else:
    print(Fore.RED + 'Not A Tool!')
    print('')
while True:
   funt()

说 #NEW CODE ABOVE 的部分是我试图绑定在一起的部分。从 secret_word 开始，然后我尝试将其与 def funt(): 开始的位置绑定。 'Bind' 我的意思是我想以工具菜单的方式创建一个菜单。我已经尝试了很多解决方案，当您输入错误的密码时仍然有问题仍然可以访问。我必须提到我正在学习编码。

Answer 1

在要求输入密码的代码周围放置一个 while 循环。输入正确的密码后，您将继续执行其余代码。

while True:
    guess = input(Fore.YELLOW + 'Enter Password: ')
    try:
      if guess != secret_word:
        print(Fore.RED + 'ACCESS DENIED')
      else:
        print(Fore.GREEN, end='')
        print('ACCESS GRANTED')
        break # leave the loop
    except:
      print('')

尝试将此代码与以下代码绑定以创建进入程序的密码的困境

Dilemma trying to bind this code with the following code to make a password to enter program

python

passwords

function