Ag-Grid中如何只导出当前页面显示的数据？

Question

默认情况下（不传递参数），当您从 ag-grid 导出数据时，它会导出所有页面中的所有数据。如何设置只导出当前页面显示的数据？

Answer 1

您可以使用 shouldRowBeSkipped 参数选项并定义导出函数，如 -

export = () => {
        var firstRow  = this.gridApi.getFirstDisplayedRow();
        var lastRow = this.gridApi.getLastDisplayedRow();
        var shouldRowBeSkipped = (params) => {
             // return true if index is less than first row or more than last row
             return params.node.rowIndex < firstRow || params.node.rowIndex > lastRow;
        }
        var params = { 
        shouldRowBeSkipped : shouldRowBeSkipped
        }
      }

根据文档 -

shouldRowBeSkipped
A callback function that will be invoked once per row in the grid. Return true to omit the row from the export.

Example 来自 ag-grid 文档