井字游戏检查玩家是否赢了的方法

Question

我仍然不熟悉 OOP 编程和编写紧凑的代码，所以我可能忽略了一些东西，我正在尝试找出一种方法来检查井字游戏中的垂直胜利和对角线胜利，我已经横了。

如果可能的话，有没有办法将其他两种方式合并到我已有的东西中？

#creates the gameboard that stores if spaces are open or not
game_board = [ [0,0,0], [0, 0, 0], [0, 0, 0,] ]
#0 = open space
#1 = O
#2 = X

#check for winners horizontaly
def find_winner():
    # y represents the y axis
    for y in range(3):
        if game_board[y][0] == game_board[y][1] == game_board[y][2] != 0:
            #returns if the X or 0 has won
            return game_board[y][0] 
    #returns 0 if no-one has won   
    return 0

Answer 1

您可以像这样添加更多 if 语句：

game_board = [ [0, 0, 0],
               [0, 0, 0],
               [0, 0, 0,] ]

def find_winner():
    for y in range(3):
        if game_board[y][0] == game_board[y][1] == game_board[y][2] != 0: # Check horizontal
            return game_board[y][0]
        if : # Check vertical
            return game_board[0][y]
    if game_board[0][0] == game_board[1][1] == game_board[2][2] != 0 or game_board[0][2] == game_board[1][1] == game_board[2][0] != 0: # Check diagonal
        return game_board[1][1]
    return 0

Answer 2

也许这会有所帮助，这是垂直和对角线检查的两个函数

# Checks for vertical row 
def win(game_board, player): 
    for x in range(len(game_board)): 
        win = True

        for y in range(len(game_board)): 
            if game_board[y][x] != player: 
                win = False
                continue

        if win == True: 
            return(win) 
    return(win) 

# Checks diagonal win 
def diag_win(game_board, player): 
    win = True
    y = 0
    for x in range(len(game_board)): 
        if game_board[x, x] != player: 
            win = False
    win = True
    if win: 
        for x in range(len(game_board)): 
            y = len(game_board) - 1 - x 
            if game_board[x, y] != player: 
                win = False
    return win

如果您有任何疑问或建议，请随时发表评论。对于上述功能，玩家是随机选择的。使用函数是一个好习惯

Answer 3

只有 3 个列表理解

所有胜利和位置

game_board = [ [1, 0, 1],
               [0, 1, 0],
               [0, 1, 0] ]

# Horizontals
h = [str(i+1) + ' Row' for i, v in enumerate(game_board) if sum(v) == 3]

# Verticals
v = [str(i+1) + ' Col' for i in range(3) if sum([j[i] for j in game_board]) == 3]

# Diagonals
d = [['Left Diag', '','Right Diag'][i+1] for i in [-1, 1] if sum([game_board[0][1+i], game_board[1][1]], game_board[2][1-i]) == 3]

if any([h,v,d]):
    print('You won on:', h, v, d)
else:
    print('No win yet')

井字游戏检查玩家是否赢了的方法

tic-tac-toe ways to check if player has won

python

processing

tic-tac-toe

只有 3 个列表理解

所有胜利和位置