Array.reduce() 在计算数组中数字的乘积时不起作用
Array.reduce() not working when calculating product of numbers in an array
晚上好,
我在 Javascript 中得到以下代码,用户可以在其中选择查看所有大于零的数字相加或计算乘积的结果,直到用户选择的那个 (该问题不要求输入验证,这就是为什么我没有添加任何验证条件):
let number = readlineSync.question("Please enter an integer greater than 0: ");
let sumOrProd = readlineSync.question('Enter "s" to compute the sum, or "p" to compute the product. ');
let arraynumbers = [...Array(Number(number)+1).keys()];
let sumNumbers = (array) => array.reduce((acc,x)=> acc + x, 0);
let multNumbers = (array) => array.reduce((acc,x)=> acc * x, 1);
let userdecision = sumOrProd.toLowerCase() === 's' ? sumNumbers(arraynumbers) : multNumbers(arraynumbers);
console.log(userdecision);
sumNumbers()
工作正常,但 multNumbers()
总是 returns 零,我不明白为什么(!?)。
我已经检查了文档和其他示例,但我不明白为什么它不起作用。
谁能帮我解决这个问题?
您的数组 arraynumbers 以 0 开头,只需删除第一项:
let number = 10;
let sumOrProd = 'p';
// Enter "s" to compute the sum, or "p" to compute the product.
let arraynumbers = [...Array(Number(number)+1).keys()];
arraynumbers.shift();
let sumNumbers = array => array.reduce((acc,x)=> acc + x, 0);
let multNumbers = array => array.reduce((acc,x)=> acc * x, 1);
let userdecision = sumOrProd.toLowerCase() === 's' ? sumNumbers(arraynumbers) : multNumbers(arraynumbers);
console.log(userdecision);
晚上好,
我在 Javascript 中得到以下代码,用户可以在其中选择查看所有大于零的数字相加或计算乘积的结果,直到用户选择的那个 (该问题不要求输入验证,这就是为什么我没有添加任何验证条件):
let number = readlineSync.question("Please enter an integer greater than 0: ");
let sumOrProd = readlineSync.question('Enter "s" to compute the sum, or "p" to compute the product. ');
let arraynumbers = [...Array(Number(number)+1).keys()];
let sumNumbers = (array) => array.reduce((acc,x)=> acc + x, 0);
let multNumbers = (array) => array.reduce((acc,x)=> acc * x, 1);
let userdecision = sumOrProd.toLowerCase() === 's' ? sumNumbers(arraynumbers) : multNumbers(arraynumbers);
console.log(userdecision);
sumNumbers()
工作正常,但 multNumbers()
总是 returns 零,我不明白为什么(!?)。
我已经检查了文档和其他示例,但我不明白为什么它不起作用。
谁能帮我解决这个问题?
您的数组 arraynumbers 以 0 开头,只需删除第一项:
let number = 10;
let sumOrProd = 'p';
// Enter "s" to compute the sum, or "p" to compute the product.
let arraynumbers = [...Array(Number(number)+1).keys()];
arraynumbers.shift();
let sumNumbers = array => array.reduce((acc,x)=> acc + x, 0);
let multNumbers = array => array.reduce((acc,x)=> acc * x, 1);
let userdecision = sumOrProd.toLowerCase() === 's' ? sumNumbers(arraynumbers) : multNumbers(arraynumbers);
console.log(userdecision);