MySQL CTE 递归加入另一个 Table
MySQL CTE Recursive With Join Another Table
伟大的开发者您好!
我有一个案例,用MySQL查询。
这里有一个示例模式 in SQL Fiddle
Table 架构:
CREATE TABLE account (
id_account varchar(50),
account_name varchar(50),
account_type varchar(4)
);
INSERT INTO account VALUES
('chiira', 'Chiira', '1110'),
('rdp', 'RDP', '1100');
CREATE TABLE account_type_master (
account_type varchar(4),
account_type_name varchar(50),
account_type_parent varchar(4)
);
INSERT INTO account_type_master VALUES
('1000', 'Master Account', null),
('1100', '2nd Master', '1000'),
('1110', '3rd Master', '1100');
所以,我有 2 个 table。
account table
===============================================================
| id_account | account_name | account_type |
===============================================================
| chiira | Chiira | 1110 |
| rdp | Chloe | 1100 |
| lotus | Lotus | 1111 |
===============================================================
account_type_master
===================================================================
| account_type | account_type_name | account_type_parent |
===================================================================
| 1000 | Master Account | null |
| 1100 | 2nd Master | 1000 |
| 1110 | 3rd Master | 1100 |
| 1111 | Last Master | 1110 |
===================================================================
所以,我的目标是获取帐户 table 的数据,所有 account_type 父级在单行中,不限制父级数量,像这样
============================================================================================
| id_account | account_name | account_type | account_parent_all |
============================================================================================
| chiira | Chiira | 1110 | 1100 => 1000 |
| rdp | Chloe | 1100 | 1000 |
| lotus | Lotus | 1111 | 1110 => 1100 => 1000 |
============================================================================================
如何实现?
谢谢:)
您可以使用此递归 CTE 查询,它查找给定 id_account
的所有父 account_type
值,然后使用 GROUP_CONCAT
将这些值连接在一起以获得 account_parent_all
值:
WITH RECURSIVE CTE AS (
SELECT a.id_account, a.account_name, a.account_type, m.account_type_parent, 0 AS depth
FROM account a
JOIN account_type_master m ON m.account_type = a.account_type
UNION ALL
SELECT c.id_account, c.account_name, c.account_type, m.account_type_parent, c.depth + 1
FROM CTE c
JOIN account_type_master m ON m.account_type = c.account_type_parent
WHERE c.account_type_parent IS NOT NULL
)
SELECT c.id_account, c.account_name, c.account_type,
GROUP_CONCAT(c.account_type_parent ORDER BY c.depth SEPARATOR ' => ') AS account_parent_all
FROM CTE c
GROUP BY c.id_account, c.account_name, c.account_type
ORDER BY c.account_name
输出:
id_account account_name account_type account_parent_all
chiira Chiira 1110 1100 => 1000
rdp Chloe 1100 1000
lotus Lotus 1111 1110 => 1100 => 1000
伟大的开发者您好!
我有一个案例,用MySQL查询。 这里有一个示例模式 in SQL Fiddle
Table 架构:
CREATE TABLE account (
id_account varchar(50),
account_name varchar(50),
account_type varchar(4)
);
INSERT INTO account VALUES
('chiira', 'Chiira', '1110'),
('rdp', 'RDP', '1100');
CREATE TABLE account_type_master (
account_type varchar(4),
account_type_name varchar(50),
account_type_parent varchar(4)
);
INSERT INTO account_type_master VALUES
('1000', 'Master Account', null),
('1100', '2nd Master', '1000'),
('1110', '3rd Master', '1100');
所以,我有 2 个 table。
account table
===============================================================
| id_account | account_name | account_type |
===============================================================
| chiira | Chiira | 1110 |
| rdp | Chloe | 1100 |
| lotus | Lotus | 1111 |
===============================================================
account_type_master
===================================================================
| account_type | account_type_name | account_type_parent |
===================================================================
| 1000 | Master Account | null |
| 1100 | 2nd Master | 1000 |
| 1110 | 3rd Master | 1100 |
| 1111 | Last Master | 1110 |
===================================================================
所以,我的目标是获取帐户 table 的数据,所有 account_type 父级在单行中,不限制父级数量,像这样
============================================================================================
| id_account | account_name | account_type | account_parent_all |
============================================================================================
| chiira | Chiira | 1110 | 1100 => 1000 |
| rdp | Chloe | 1100 | 1000 |
| lotus | Lotus | 1111 | 1110 => 1100 => 1000 |
============================================================================================
如何实现? 谢谢:)
您可以使用此递归 CTE 查询,它查找给定 id_account
的所有父 account_type
值,然后使用 GROUP_CONCAT
将这些值连接在一起以获得 account_parent_all
值:
WITH RECURSIVE CTE AS (
SELECT a.id_account, a.account_name, a.account_type, m.account_type_parent, 0 AS depth
FROM account a
JOIN account_type_master m ON m.account_type = a.account_type
UNION ALL
SELECT c.id_account, c.account_name, c.account_type, m.account_type_parent, c.depth + 1
FROM CTE c
JOIN account_type_master m ON m.account_type = c.account_type_parent
WHERE c.account_type_parent IS NOT NULL
)
SELECT c.id_account, c.account_name, c.account_type,
GROUP_CONCAT(c.account_type_parent ORDER BY c.depth SEPARATOR ' => ') AS account_parent_all
FROM CTE c
GROUP BY c.id_account, c.account_name, c.account_type
ORDER BY c.account_name
输出:
id_account account_name account_type account_parent_all
chiira Chiira 1110 1100 => 1000
rdp Chloe 1100 1000
lotus Lotus 1111 1110 => 1100 => 1000