在 pandas 数据帧的列中将 NaN 值更改为 0 时出现问题

Question

我想了解这是如何工作的..

我有这个df。

   ticket_id                      address grafitti_status
0     284932  10041 roseberry, Detroit MI             NaN
1     285362  18520 evergreen, Detroit MI             NaN
2     285361  18520 evergreen, Detroit MI             NaN
3     285338     1835 central, Detroit MI             NaN
4     285346     1700 central, Detroit MI             NaN
5     285345     1700 central, Detroit MI             NaN

哪里

In: df.grafitti_status.unique()
Out: array([nan, 'GRAFFITI TICKET'], dtype=object)

所以我正在尝试将 NaN 更改为 0，将 'GRAFFITI TICKET' 更改为 1。

我用过

df.loc[df['grafitti_status'] == 'GRAFFITI TICKET', 'grafitti_status'] = 1

效果很好，但“0”也一样

df.loc[df['grafitti_status'] == np.nan, 'grafitti_status'] = 0

Out: array([nan, 1], dtype=object)

不起作用，因为 NaN 值仍然存在..

和

df['grafitti_status'] = df['grafitti_status'].replace({np.nan:0,'GRAFFITI TICKET':1},inplace=True)

也不起作用，将所有内容替换为 None。

    ticket_id   address grafitti_status
0   284932  10041 roseberry, Detroit MI None
1   285362  18520 evergreen, Detroit MI None
2   285361  18520 evergreen, Detroit MI None
3   285338  1835 central, Detroit MI    None
4   285346  1700 central, Detroit MI    None
5   285345  1700 central, Detroit MI    None
6   285347  1700 central, Detroit MI    None

任何人都可以告诉我为什么它以这种方式工作吗？

我终于发现我可以用

达到我想要的结果

df.loc[df['grafitti_status'] == 'GRAFFITI TICKET', 'grafitti_status'] = 1
df['grafitti_status'] = df['grafitti_status'].fillna(0)

Out: array([0, 1], dtype=int64)

这会导致以下警告消息。

C:\Users\Maria\Anaconda3\lib\site-packages\pandas\core\indexing.py:543: SettingWithCopyWarning: 
A value is trying to be set on a copy of a slice from a DataFrame.
Try using .loc[row_indexer,col_indexer] = value instead

See the caveats in the documentation: http://pandas.pydata.org/pandas-docs/stable/indexing.html#indexing-view-versus-copy
  self.obj[item] = s
C:\Users\Maria\Anaconda3\lib\site-packages\ipykernel_launcher.py:3: SettingWithCopyWarning: 
A value is trying to be set on a copy of a slice from a DataFrame.
Try using .loc[row_indexer,col_indexer] = value instead

所以我仍然不确定正确的方法是什么？

Answer 1

自

np.nan==np.nan 会 return 错误

我们有函数isna

df.loc[df['grafitti_status'].isna(), 'grafitti_status'] = 0

在 pandas 数据帧的列中将 NaN 值更改为 0 时出现问题

Problem with changing NaN values to 0 in a column of a pandas dataframe

python

replace

nan

dataframe

pandas