Python Selenium：如何等到 href 属性包含特定字符串？

Question

例如，我在 Selenium 中打开页面 https://example.com/page-1/，寻找包含 domain.com 的特定 link。现在我正在使用 sleep(20) 来确保页面已完全加载。但我想知道我是否可以使用 WebDriverWait 不仅用于标记存在，而且还用于它的包含存在。尚未找到任何解决方案...

Answer 1

您可以尝试这样的操作，我假设您使用的是 Firefox，但逻辑是相同的：

firefox = webdriver.Firefox()
firefox.get('https://example.com/page-1/')
#wait for a maximum of 60 seconds in this example
wait = WebDriverWait(firefox, 60)
domain = "domain.com"
wait.until(lambda x: x.find_element_by_css_selector(f"a[href*='{domain}']"))

Answer 2

等待 for the href attribute to contain a specific string, you can induce for the visibility_of_element_located() and you can use either of the following :

domain.com的完全匹配：

使用CSS_SELECTOR:

element = WebDriverWait(browser, 20).until(EC.visibility_of_element_located((By.CSS_SELECTOR, "a[href='domain.com']")))

使用XPATH:

element = WebDriverWait(browser, 20).until(EC.visibility_of_element_located((By.XPATH, "//a[@href='domain.com']")))

domain.com的部分匹配：

使用CSS_SELECTOR:

element = WebDriverWait(browser, 20).until(EC.visibility_of_element_located((By.CSS_SELECTOR, "a[href*='domain.com']")))

使用XPATH:

element = WebDriverWait(browser, 20).until(EC.visibility_of_element_located((By.XPATH, "//a[contains(@href, 'domain.com')]")))

注意：您必须添加以下导入：

from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.common.by import By
from selenium.webdriver.support import expected_conditions as EC

Python Selenium：如何等到 href 属性包含特定字符串？

Python Selenium: How to wait until href attribute contains a specific string?

python

selenium

xpath

css-selectors

webdriverwait