有没有办法找出我的错误在哪里？

Question

我正在尝试创建 Verilog 代码以在 Hneemann's Digital 上生成秒表，但出现了一些错误。没有迹象表明我的错误在哪里，所以我无法确定在哪里寻找它们。我会 post 下面的代码，看看是否有人能发现它。

module cronometro(

    input clk,
    input rst,
    input [6:0] minuto,
    input start,
    output [6:0] m1,
    output [6:0] m2,
    output [6:0] s3,
    output [6:0] s4

);

parameter q0 = 3'd0,  q1 = 3'd1, q2 = 3'd2, q3 = 3'd3, q4 = 3'd4, q5 = 3'd5;

    reg [7:0] a, b, n;
    reg [7:0] snA, snB, snN;
    reg [2:0] cs, ns;

    

always @(*)
begin
   case(cs)

            q0: ns = q1; 
            q1: ns = a!= n? q2:q6;
            q2: ns = q3;
            q3: ns = b!=8'd60? q2:q4;
            q4:ns = q1;
            q5: ns = q5;
            default: begin
                ns = q0; 
            end
    endcase

         always @(posedge clk) begin
        if(rst)
            cs <= q0;
        else 
            cs <= ns;
        end

    always @(posedge clk) begin
        a <= snA;
        b <= snB;
    end

 always @(*) begin

        if (enabled) begin
        case(cs)

            q0: begin
                snA = 8'd0;  
                snB = 8'd0;  
                snN = minuto;            
            end

            q1: begin
                snA = a;  
                snB = b;  
                snN = minuto; 
            end
            
            q2: begin
                snA = a;  
                snB = b + 8'd1; 
                snN = minuto;  
            end
            
            q3: begin
                snA = a;  
                snB = b;  
                snN = minuto; 
            end
            
            q4: begin
                snA = a + 8'd1;  
                snB = 8'd0;  
                snN = minuto; 
            end
            
            q5: begin
                snA = a;  
                snB = b; 
                snN = minuto;  
            end
            

            default: begin
                snA = 8'd0;  
                snB = 8'd0; 
                snN = minuto;
            end
        endcase 
        end
    end

end

endmodule

错误是：

jdoodle.v:37: 语法错误

jdoodle.v:39: 赋值语句左值语法。

jdoodle.v:40: 语法错误

jdoodle.v:41: 赋值语句左值语法。

jdoodle.v:100: 语法错误

我放弃了

Answer 1

由于以下原因，我遇到了几个编译错误：

不匹配 begin/end 由于缩进不一致。
未声明的信号：enabled、q6
? 运算符周围缺少空格。

当您不理解错误消息时，请在其他模拟器上尝试您的代码，例如 edaplayground.

上的模拟器

这段代码对我来说编译没有错误：

module cronometro(

    input clk,
    input rst,
    input [6:0] minuto,
    input start,
    output [6:0] m1,
    output [6:0] m2,
    output [6:0] s3,
    output [6:0] s4

);

parameter q0 = 3'd0,  q1 = 3'd1, q2 = 3'd2, q3 = 3'd3, q4 = 3'd4, q5 = 3'd5;

    reg [7:0] a, b, n;
    reg [7:0] snA, snB, snN;
    reg [2:0] cs, ns;

reg enabled, q6;

always @(*)
begin
   case(cs)

            q0: ns = q1; 
            q1: ns = a != n ? q2 : q6;
            q2: ns = q3;
            q3: ns = b != 8'd60 ? q2 : q4;
            q4:ns = q1;
            q5: ns = q5;
            default: begin
                ns = q0; 
            end
    endcase
end

always @(posedge clk) begin
        if(rst)
            cs <= q0;
        else 
            cs <= ns;
end

always @(posedge clk) begin
    a <= snA;
    b <= snB;
end

always @(*) begin

        if (enabled) begin
        case(cs)

            q0: begin
                snA = 8'd0;  
                snB = 8'd0;  
                snN = minuto;            
            end

            q1: begin
                snA = a;  
                snB = b;  
                snN = minuto; 
            end
            
            q2: begin
                snA = a;  
                snB = b + 8'd1; 
                snN = minuto;  
            end
            
            q3: begin
                snA = a;  
                snB = b;  
                snN = minuto; 
            end
            
            q4: begin
                snA = a + 8'd1;  
                snB = 8'd0;  
                snN = minuto; 
            end
            
            q5: begin
                snA = a;  
                snB = b; 
                snN = minuto;  
            end
            

            default: begin
                snA = 8'd0;  
                snB = 8'd0; 
                snN = minuto;
            end
        endcase 
        end
end

endmodule

有没有办法找出我的错误在哪里？

Is there a way I can find out where my error is?

verilog