select并显示与用户提示的ename具有相同deptno和mgr的employess

select and display employess who have the same deptno and mgr as the prompted ename by the user

显示与给定员工(提示)具有相同DEPTNO和MGR的员工,不包括该员工。 谁能帮我解决这个问题并告诉我如何排除用户提供的员工。

select ename,deptno,mgr from emp where 
deptno=(select deptno from emp where ename='&&ename') 
AND 
mgr=(select mgr from emp where ename='&ename');

例如:

SQL> select deptno, empno, ename, mgr
  2  from emp
  3  order by deptno, mgr;

    DEPTNO      EMPNO ENAME             MGR
---------- ---------- ---------- ----------
        10       7934 MILLER           7782
        10       7782 CLARK            7839
        10       7839 KING
        20       7788 SCOTT            7566
        20       7902 FORD             7566
        20       7876 ADAMS            7788
        20       7566 JONES            7839
        20       7369 SMITH            7902
        30       7521 WARD             7698  --> we'll watch these
        30       7499 ALLEN            7698  -->
        30       7844 TURNER           7698  -->
        30       7900 JAMES            7698  -->
        30       7654 MARTIN           7698  --> employees
        30       7698 BLAKE            7839

14 rows selected.

查询:第 3 - 6 行 select 具有相同 DEPTNOMGR 的人,而第 7 行排除了那个员工(由 PAR_EMPNO 标识) .

SQL> select e.*
  2  from emp e
  3  where (e.deptno, e.mgr) = (select a.deptno, a.mgr
  4                             from emp a
  5                             where a.empno = &&par_empno
  6                            )
  7    and e.empno <> &&par_empno;
Enter value for par_empno: 7521

     EMPNO ENAME      JOB              MGR HIREDATE          SAL       COMM     DEPTNO
---------- ---------- --------- ---------- ---------- ---------- ---------- ----------
      7499 ALLEN      SALESMAN        7698 02/20/1981       1600        300         30
      7654 MARTIN     SALESMAN        7698 09/28/1981       1250       1400         30
      7844 TURNER     SALESMAN        7698 09/08/1981       1500          0         30
      7900 JAMES      CLERK           7698 12/03/1981        950                    30

SQL>