如何为每第 n 个句子换行？

Question

苦于如何在长文本字符串中每第 5 个句子添加一个新行。

输入示例

text = 'The puppy is cute. Summer is great. Happy Friday. Sentence4. Sentence5. Sentence6. Sentence7.

期望的输出：

The puppy is cute. Summer is great. Happy friday. Sentence4. Sentence5.
Sentence6. Sentence7.

有人可以帮忙吗？

Answer 1

试试这个：

text = 'The puppy is cute. Summer is great. Happy friday. sentence4. sentence5. sentence6. sentence7.'
splittext = text.split(".")
for x in range(5, len(splittext), 5):
    splittext[x] = "\n"+splittext[x].lstrip()
text = ".".join(splittext)
print(text)

Answer 2

使用正则表达式。在“[not .] followed by .”的 5 个匹配项后添加 \n。

import re
text = 'The puppy is cute. Summer is great. Happy friday. sentence4. sentence5. sentence6. sentence7.'

print(re.sub(r'((?:[^.]+\.\s*){5})',r'\n',text))

一个更高级的正则表达式句子匹配器，通过匹配结束标点符号来处理缩写和其他标点符号。
参考：https://mikedombrowski.com/2017/04/regex-sentence-splitter/
注意：仍然存在失败的边缘情况，例如 T.V。后跟 Mr. needs 两个空格来表示一个单独的句子。带有句子的引文将被拆分。等等

import re
sentence_regex = r'((.*?([\.\?!][\'\"\u2018\u2019\u201c\u201d\)\]]*\s*(?<!\w\.\w.)(?<![A-Z][a-z][a-z]\.)(?<![A-Z][a-z]\.)(?<![A-Z]\.)\s+)){5})'
text = 'The puppy is cute. Watch T.V.  Mr. Summers is great. Say "my name."  My name is.  Or not... Happy friday? Sentence4. Sentence5. Sentence6. Sentence7.'
text += " " + text

print(re.sub(sentence_regex,r'\n',text))

如果比这更复杂，您可能需要研究语言处理工具包。

Answer 3

这是一个在第 5 句末尾添加换行符的简单函数

def new_line(sentence: str):
    # characters that mark the end of a sentence
    end_of_sentence_markers = ['.', '!', '?', '...']
    # after n sentences insert new_line
    n = 5

    # keeps track 
    count = 0
    # final string as list for efficiency
    final_str = []
    # split at space
    sentence_split = sentence.split(' ')

    # traverse the sentence split
    for word in sentence_split:
        # if end of sentence is present then increase count
        if word[-1] in end_of_sentence_markers:
            count += 1
        # if count is equal to n then add newline otherwise add space
        if count == n:
            final_str.append(word + '\n')
            count = 0
        else:
            final_str.append(word + ' ')


    # return the string version of the list
    return ''.join(final_str)

这是修改后的版本：

def new_line_better(sentence: str, n: int):
    # final string as list for efficiency
    final_str = []
    # split at period and remove extra spaces
    sentence_split = list( map( lambda x : x.strip(),  sentence.split('.') ) )
    # pop off last space
    sentence_split.pop()
    
    # keeps track 
    count = 0
    # traverse the sentences
    for sentence in sentence_split:
        count += 1
        if count == n:
            count = 0
            final_str.append(sentence+'.\n')
        else:
            final_str.append(sentence+'. ')

    # return the string version of the list
    return ''.join(final_str)

Answer 4

另一种方法：

text = 'The puppy is cute. Summer is great. Happy friday. sentence4. sentence5. sentence6. sentence7.'

out = ''
for i, e in enumerate(text.split(".")):
    if (i > 0)  & (i % 5 == 0):
        out = out + '\n'
    out = out + e + '.'
out

结果：

'The puppy is cute. Summer is great. Happy friday. sentence4. sentence5.\n sentence6. sentence7..'

Answer 5

有列表理解

text = 'The puppy is cute. Summer is great. Happy friday. sentence4. sentence5. sentence6. sentence7.'
lines = text.split(".")
result = ".".join([l if i % 5 else "\n"+l for (i, l) in enumerate(lines)]).lstrip()
print(result)

如何为每第 n 个句子换行？

How to put a newline for every n'th sentence?

python

string

newline