拆分列表中的数组

Question

我有一个列表，其中有一个像

这样的数组

ListA = [('8', array([[422, 769, 468, 789],
         [422, 739, 468, 759],
         [422, 709, 468, 729],
         [422, 545, 468, 565],
         [422, 515, 468, 535]]), 'A'),
         ('8', array([[423, 483, 466, 506]]), 'A'),
         ('8', [], 'B'),
         ('9', array([[375, 579, 414, 619],
         [375, 549, 414, 589],
         [375, 519, 414, 559]]), 'C')]

现在列表中的数组将以这样的方式拆分，输出看起来像

ListA = [('8', [422, 769, 468, 789], 'A'),
         ('8', [422, 739, 468, 759], 'A'),
         ('8', [422, 709, 468, 729], 'A'),
         ('8', [422, 545, 468, 565], 'A'),
         ('8', [422, 515, 468, 535], 'A'),
         ('8', [423, 483, 466, 506], 'A'),
         ('8', [], 'B'),
         ('9', [375, 579, 414, 619], 'C'),
         ('9', [375, 549, 414, 589], 'C'),
         ('9', [375, 519, 414, 559], 'C')]

有什么办法可以做到这一点吗？

Answer 1

output = []
for line in ListA:
    number, arr, char = line
    if len(arr) == 0:  #append empty row
        output.append((number, [], char))

    for row in arr:
        output.append((number, row, char))

Answer 2

这是 flatmap 的工作：

def flatmap(func, *iterable):
    return itertools.chain.from_iterable(map(func, *iterable))

def tuplewitharray_to_listoftuples(t):
    n, arr, c = t
    if len(arr) > 0:
        return [(n, row, c) for row in arr]
    else:
        return [(n, [], c)]

list(flatmap(tuplewitharray_to_listoftuples, ListA))

输出：

[('8', [422, 769, 468, 789], 'A'),
 ('8', [422, 739, 468, 759], 'A'),
 ('8', [422, 709, 468, 729], 'A'),
 ('8', [422, 545, 468, 565], 'A'),
 ('8', [422, 515, 468, 535], 'A'),
 ('8', [423, 483, 466, 506], 'A'),
 ('8', [], 'B'),
 ('9', [375, 579, 414, 619], 'C'),
 ('9', [375, 549, 414, 589], 'C'),
 ('9', [375, 519, 414, 559], 'C')]

拆分列表中的数组

Split the array in a list

arrays

nested-lists

python-3.x