Pyomo：构建抽象模型

Question

我正在尝试使用 Pyomo（求解器 Ipopt）进行优化。

我有 2 组（j 代表发电机数量，t 代表时间），6 个索引参数（A、B、C、Pmin、Pmax：索引在 model.J，需求索引在 model.T)

我要做的是根据24种不同的需求生成24种不同的成本。

我运行代码后，出现了这个错误：

TypeError: P_LoadgenBalance() 采用 1 个位置参数，但给出了 2 个。

我不知道为什么会出现这个错误，希望你能帮助我。感谢您的帮助！

薇薇

from pyomo.environ import *
import matplotlib.pyplot as plt
import numpy as np

# create a model
model = AbstractModel()

#     There are ten generators with different values of ABC.
#     Minimizing the costs and find the optimal dispatch for 24 different demands changed with time  
#     obj：Cost= sum(ap^2 +bp+c)
#     constraints: sum_i P(i,t)  >= load(t) , (Pmin =< P =< Pmax).

# declare decision variables

model.M = Param(mutable=True)
model.T = RangeSet(model.M)
model.N = Param(mutable=True)
model.J = RangeSet(model.N)
model.A = Param(model.J)
model.B = Param(model.J)
model.C = Param(model.J)
model.D = Param(model.J)
model.E = Param(model.J)
model.F = Param(model.J)
model.P_min = Param(model.J, within=PositiveReals)
model.P_max = Param(model.J, within=PositiveReals)
model.demand = Param(model.T)
model.emission_value = Param(initialize=1000000, mutable=True)

# declare constraints_Pbounds (Pmin =< P =< Pmax)

def Pbounds(model, j,t):
    return (model.P_min[j], model.P_max[j])
model.P = Var(model.J, model.T, bounds=Pbounds, domain=NonNegativeReals)

# declare constraints_P_LoadgenBalance  ( sum P >= demand)

def P_LoadgenBalance(model,t):
    return sum(model.P[j,t] for j in model.J  ) >= model.demand[t]
model.P_LoadgenBalance = Constraint(model.T, rule=P_LoadgenBalance)


# declare objective_cost

def obj_cost(model):
     return sum(model.A[j]* model.P[j,t] ** 2 + model.B[j] * model.P[j,t] + model.C[j] for j in model.J for t in model.T) 
model.cost= Objective(rule=obj_cost, sense=minimize)

# declare objective_emission

def obj_emission(model):
      return sum(model.E[j]* model.P[j,t] ** 2 + model.D[j] * model.P[j,t] + model.F[j] for j in model.J for t in model.T) 
model.emission= Objective(rule=obj_emission, sense=minimize)

model.emission.deactivate()
opt = SolverFactory('Ipopt')
instance = model.create_instance("E:\pycharm_project\END-10units.dat")
results = opt.solve(instance)

print(value(instance.cost)

数据文件

param M:=24;
param N:=10;
# Creating Parameters A, B, C,D,E,F, P_min, P_max:
param : A B C D E F P_min P_max:=
1   0.0148  12.1    82  2.15    3.59    -11.4   80  200
2   0.0289  12.6    49  3.63    2.02    -3.65   120 320
3   0.0135  13.2    100 3.3     4.7     -4.04   50  150
4   0.0127  13.9    105 3.73    1.61    -13.44  250 520
5   0.0261  13.5    72  2.27    2.29    -4.41   80  280
6   0.0212  15.4    29  2.37    2.77    -8.61   50  150
7   0.0382  14      32  2.03    4.86    -8.91   30  120
8   0.0393  13.5    40  2.4     3.32    -31.74  30  110
9   0.0396  15      25  2.5     4.03    -19.14  20  80
10  0.051   14.3    15  3.43    3.27    -21.02  20  60

param demand:=
1 600
2 650
3 680
4 651
5 630
6 650
7 810
8 820
9 883
10 893
11 888
12 901
13 892
14 875
15 843
16 877
17 880
18 904
19 865
20 855
21 766
22 733
23 688
24 654;

Answer 1

您没有在函数 P_LoadgenBalance 中定义 t，所以 t 是另一个预期的参数。代码应该是这样的：

def P_LoadgenBalance(model ,t):

为了存储单个成本，您必须使用新的 objective 函数为其创建一个变量，如下所示：

# Cost Variable to store individual cost per j through t
model.X = Var(model.J, model.T, domain=NonNegativeReals)


# Cost Function

def cost(model, j, t):
    return model.X[j, t]  == model.A[j] * model.P[j, t] ** 2 + model.B[j] * model.P[j, t] + model.C[j]


model.cost = Constraint(model.T, Model.J, rule=cost)

# Objective
def obj_cost(model):
    return sum(model.X[j, t] for j in model.J for t in model.T)


model.total_cost = Objective(rule=obj_cost, sense=minimize)

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