CASE 条件和 SUM() 常用 table 表达式或 Group By

CASE condition and SUM() common table expressions or Group By

希望有人能帮忙?我有一个第三方软件,我可以进行自定义 sql 查询但不能更改任何数据库。努力得到我想要的结果。

我是使用 GROUP BY 还是 CTE 来获得我需要的结果?

WITH CTE AS ( 
SELECT  tblTicketsSummary.fldDateScheduled AS [Scheduled], 
tblTicketsRow.fldStartTime  AS [TIME], tblTicketsRow.fldPs AS 
[s],tblTicketsRow.fldPrice AS PR, 
tblTicketsSummary.fldFirstName+' '+tblTicketsSummary.fldLastName 
AS [Client], ROW_NUMBER() OVER 
(PARTITION BY tblTicketsSummary.fldTicketID ORDER BY 
tblTicketsRow.fldTicketID) AS C, tblTicketsSummary.fldDateClosed 
AS [Date Closed],
 CASE WHEN tblTicketsRow.fldPs ='p' THEN tblTicketsRow.fldPrice  
ELSE £0.00 END AS Product,  
CASE WHEN tblTicketsRow.fldPs ='s' THEN tblTicketsRow.fldPrice  
ELSE £0.00 END AS Services, 
FROM tblTicketsSummary INNER JOIN 
tblTicketsRow ON tblTicketsSummary.fldTicketID = tblTicketsRow.fldTicketID
 WHERE (fldDateVoided IS NULL) AND (NOT(fldDateClosed IS NULL)) 
GetUserDate('AND','fldDateClosed','') AND tblTicketsRow.fldEmployeeName ='Tina Young' 
 AND tblTicketsSummary.fldTotal >1 )
SELECT * FROM  CTE   ORDER BY   Scheduled ASC,  TIME ASC

这给我下面的结果。我已经删除了最后一个 select 中的 Where c=1 ,我将把它放回最终查询中,它按时间给我第一个结果,这就是我想要的。我正在努力的一点是。我想将所有产品的价格和所有服务的价格加在一起,得出销售的产品和服务总数。然后在最终查询中将服务和产品合计起来。

Scheduled   TIME s   PR      Client   C Date Closed Product  Services  Total
17/07/2020 17:00 S £10.00 Ben Preston 1 17/07/2020  £0.00    £10.00     s+p
17/07/2020 17:45 S £1.00  Ben Preston 2 17/07/2020  £0.00    £1.00      s+p
17/07/2020       P £19.00 Ben Preston 3 17/07/2020  £19.00   £0.00      s+p
17/07/2020       P £10.00 Ben Preston 4 17/07/2020  £10.00   £0.00      s+p

我想要的结果如下。查询的最后部分如下。我只能在第 3 方软件中自定义查询。

 SELECT * FROM  CTE  WHERE c=1 ORDER BY   Scheduled ASC,  TIME ASC 


Scheduled  TIME   Client       C   Date Closed  Product Services   Total
17/07/2020 17:00 Ben Preston   1   17/07/2020   £29.00   £11.00    £40.00

我希望我已经格式化了这个权利以便人们理解。感谢您提供的任何帮助。

似乎您只需要将两个 Group Sums 添加到您现有的 CTE,然后将它们添加到您的最终 Select:

WITH CTE AS ( 
SELECT  tblTicketsSummary.fldDateScheduled AS [Scheduled], 
   tblTicketsRow.fldStartTime  AS [TIME], 
   tblTicketsRow.fldPs AS [s],tblTicketsRow.fldPrice AS PR, 
   tblTicketsSummary.fldFirstName+' '+tblTicketsSummary.fldLastName AS [Client], 
   ROW_NUMBER() 
   OVER (PARTITION BY tblTicketsSummary.fldTicketID
         ORDER BY tblTicketsRow.fldStartTime) AS C, 
   tblTicketsSummary.fldDateClosed AS [Date Closed],
   
   SUM(CASE WHEN tblTicketsRow.fldPs ='p' THEN tblTicketsRow.fldPrice ELSE £0.00 END)
   OVER (PARTITION BY tblTicketsSummary.fldTicketID) AS Product,  
   
   SUM(CASE WHEN tblTicketsRow.fldPs ='s' THEN tblTicketsRow.fldPrice ELSE £0.00 END)
   OVER (PARTITION BY tblTicketsSummary.fldTicketID) AS Services
FROM tblTicketsSummary
INNER JOIN tblTicketsRow
ON tblTicketsSummary.fldTicketID = tblTicketsRow.fldTicketID
WHERE (fldDateVoided IS NULL) AND (NOT(fldDateClosed IS NULL)) 
--GetUserDate('AND','fldDateClosed','') AND tblTicketsRow.fldEmployeeName ='Tina Young' 
 AND tblTicketsSummary.fldTotal >1 )
SELECT cte.*,
   Product + Services as total
FROM  CTE
WHERE C = 1
ORDER BY   Scheduled ASC,  TIME ASC;

顺便说一句,ROW_NUMBER 上的 ORDER BY tblTicketsRow.fldTicketID 不是基于唯一的列,因此无法保证行的顺序。您可能需要 order by tblTicketsRow.fldStartTime