将 JSON 解析为 Swift 时消除快速类型附件方法

Question

我注意到虽然 Quicktype.io 在将 JSON 解析为 SWIFt 方面做得很好，但有时它会求助于很多辅助功能和方法。对于以下内容，它生成了大约 15 个额外的方法。其中一些很熟悉，例如 NSNull，但是，有两个对我来说并不熟悉，例如 JSONAny，似乎应该有办法绕过它们。例如，JSONAny class 中有大约 12 个函数，它仅用于解析一个对我来说不那么重要的字段。

这是 JSON 的样子：

[{"name":"Afghanistan","topLevelDomain":[".af"],"alpha2Code":"AF","alpha3Code":"AFG","callingCodes":["93"],"capital":"Kabul","altSpellings":["AF","Afġānistān"],"region":"Asia","subregion":"Southern Asia","population":27657145,"latlng":[33.0,65.0],"demonym":"Afghan","area":652230.0,"gini":27.8,"timezones":["UTC+04:30"],"borders":["IRN","PAK","TKM","UZB","TJK","CHN"],"nativeName":"افغانستان","numericCode":"004","currencies":[{"code":"AFN","name":"Afghan afghani","symbol":"؋"}],"languages":[{"iso639_1":"ps","iso639_2":"pus","name":"Pashto","nativeName":"پښتو"},{"iso639_1":"uz","iso639_2":"uzb","name":"Uzbek","nativeName":"Oʻzbek"},{"iso639_1":"tk","iso639_2":"tuk","name":"Turkmen","nativeName":"Türkmen"}],"translations":{"de":"Afghanistan","es":"Afganistán","fr":"Afghanistan","ja":"アフガニスタン","it":"Afghanistan","br":"Afeganistão","pt":"Afeganistão","nl":"Afghanistan","hr":"Afganistan","fa":"افغانستان"},"flag":"https://restcountries.eu/data/afg.svg","regionalBlocs":[{"acronym":"SAARC","name":"South Asian Association for Regional Cooperation","otherAcronyms":[],"otherNames":[]}],"cioc":"AFG"}]

我不会给出该结构比主结构低一级的所有代码：

 struct CountryReturnedElement: Codable {
       //...various fields  
        let regionalBlocs: [RegionalBloc]
    }

   // MARK: - RegionalBloc
    struct RegionalBloc: Codable {
        let acronym, name: String
        let otherAcronyms, otherNames: [JSONAny]
    }

它仅用于解码以下 JSON:

"regionalBlocs":[{"acronym":"SAARC","name":"South Asian Association for Regional Cooperation","otherAcronyms":[],"otherNames":[]}]

是否有一种简单的方法来解析上述内容，而无需借助具有 15 个函数和方法的辅助 classes。我很可能，otherAcronyms 和 otherNames 是字符串，所以我想我可以去 [String?]。但是，我想我不知道有 100% 的把握，更像是 95% 的把握。

感谢您的任何建议。

Answer 1

如果您确定 otherAcronyms 和 otherNames 键 return [String?] 您可以修改 RegionalBloc 结构以接受 [String?] .

struct RegionalBloc: Codable {
    let acronym, name: String
    let otherAcronyms, otherNames: [String?]
}

您可以简单地尝试一下，如果 JSONDecoder 没有抛出任何错误，您就可以继续 [String?]。否则，你可以检查错误并打印到控制台来检查传入类型并设置它。

将 JSON 解析为 Swift 时消除快速类型附件方法

Eliminating quicktype accessory methods when parsng JSON to Swift

json

ios

swift

jsondecoder