如何使用 subprocess.popen

Question

为什么我在运行 subprocess.popen 时出现错误？

我加载了一个带有变量参数的命令，我进行了拆分并将结果传递给 subprocess.Popen。 它returns一个错误。

非常感谢大家的配合

完整代码如下：

#!/usr/bin/python3
# -*- coding: utf-8 -*-

import subprocess
import shlex


def main():
    try:
            data = "ls -al"
            args = shlex.split(data)
            comando = subprocess.Popen(args, shell=True,stdout=subprocess.PIPE,stderr=subprocess.PIPE)

            if comando.stderr.read() != "":
                print("[-] Error")
            else:
                print(comando.stdout.read())
    except Exception as e:
        print (e)

if __name__ == '__main__' :
    try:
        main()
    except KeyboardInterrupt:
        exit()

Answer 1

使用communicate

#!/usr/bin/python3
# -*- coding: utf-8 -*-

import subprocess
import shlex


def main():
    try:
            data = "ls -al"
            args = shlex.split(data)
            comando = subprocess.Popen(args, shell=True,stdout=subprocess.PIPE,stderr=subprocess.PIPE)
            comando_stdout, comando_stderr = comando.communicate()
            if comando_stderr:
                print("[-] Error")
            else:
                print(comando_stdout)
    except Exception as e:
        print (e)

if __name__ == '__main__' :
    try:
        main()
    except KeyboardInterrupt:
        exit()

如何使用 subprocess.popen

How subprocess.popen is used

python

subprocess