CS50 - PSet4(滤镜) - 模糊
CS50 - PSet4 (Filter) - Blur
我运行正在编写以下代码
void blur(int height, int width, RGBTRIPLE image[height][width])
{
for (int i = 0; i < height; i++)
{
for (int j = 0; j < width; j++)
{
int div = 1;
if ( j + 1 < width - 1 && j + 1 > 0)
{
div++;
}
else
{
image[i][j + 1].rgbtRed = 0;
image[i][j + 1].rgbtRed = 0;
image[i][j + 1].rgbtRed = 0;
}
if ( i + 1 < height - 1 && i + 1 > 0)
{
div++;
}
else
{
image[i + 1][j].rgbtRed = 0;
image[i + 1][j].rgbtRed = 0;
image[i + 1][j].rgbtRed = 0;
}
if ( j + 1 < width - 1 && j + 1 > 0 && i + 1 < height - 1 && i + 1 > 0)
{
div++;
}
else
{
image[i + 1][j + 1].rgbtRed = 0;
image[i + 1][j + 1].rgbtRed = 0;
image[i + 1][j + 1].rgbtRed = 0;
}
if ( i - 1 < height - 1 && i - 1 > 0)
{
div++;
}
else
{
image[i - 1][j].rgbtRed = 0;
image[i - 1][j].rgbtRed = 0;
image[i - 1][j].rgbtRed = 0;
}
if ( i - 1 < height - 1 && i - 1 > 0 && j + 1 < width - 1 && j + 1 > 0)
{
div++;
}
else
{
image[i - 1][j + 1].rgbtRed = 0;
image[i - 1][j + 1].rgbtRed = 0;
image[i - 1][j + 1].rgbtRed = 0;
}
if ( j - 1 < width - 1 && j - 1 > 0)
{
div++;
}
else
{
image[i][j - 1].rgbtRed = 0;
image[i][j - 1].rgbtRed = 0;
image[i][j - 1].rgbtRed = 0;
}
if ( j - 1 < width - 1 && j - 1 > 0 && i + 1 < height - 1 && i + 1 > 0)
{
div++;
}
else
{
image[i + 1][j - 1].rgbtRed = 0;
image[i + 1][j - 1].rgbtRed = 0;
image[i + 1][j - 1].rgbtRed = 0;
}
if ( j - 1 < width - 1 && j - 1 > 0 && i - 1 < height - 1 && i - 1 > 0)
{
div++;
}
else
{
image[i - 1][j - 1].rgbtRed = 0;
image[i - 1][j - 1].rgbtRed = 0;
image[i - 1][j - 1].rgbtRed = 0;
}
int averageR = (float)(image[i][j].rgbtRed + image[i][j + 1].rgbtRed + image[i][j - 1].rgbtRed + image[i + 1][j].rgbtRed + image[i - 1][j].rgbtRed + image[i + 1][j + 1].rgbtRed + image[i + 1][j - 1].rgbtRed + image[i - 1][j + 1].rgbtRed + image[i + 1][j - 1].rgbtRed) / div;
int averageG = (float)(image[i][j].rgbtGreen + image[i][j + 1].rgbtGreen + image[i][j - 1].rgbtGreen + image[i + 1][j].rgbtGreen + image[i - 1][j].rgbtGreen + image[i + 1][j + 1].rgbtGreen + image[i + 1][j - 1].rgbtGreen + image[i - 1][j + 1].rgbtGreen + image[i + 1][j - 1].rgbtGreen) / div;
int averageB = (float)(image[i][j].rgbtBlue + image[i][j + 1].rgbtBlue + image[i][j - 1].rgbtBlue + image[i + 1][j].rgbtBlue + image[i - 1][j].rgbtBlue + image[i + 1][j + 1].rgbtBlue + image[i + 1][j - 1].rgbtBlue + image[i - 1][j + 1].rgbtBlue + image[i + 1][j - 1].rgbtBlue) / div;
image[i][j].rgbtRed = round(averageR);
image[i][j].rgbtGreen = round(averageG);
image[i][j].rgbtBlue = round(averageB);
}
}
return;
}
不幸的是,每次我尝试 运行 它的模糊部分时,它都会出现此消息:
UndefinedBehaviorSanitizer:DEADLYSIGNAL
==8771==ERROR: UndefinedBehaviorSanitizer: SEGV on unknown address 0x7f7a4ec2890a (pc 0x000000427faa bp 0x7ffd07cd9170 sp 0x7ffd07cd7560 T8771)
==8771==The signal is caused by a WRITE memory access.
#0 0x427fa9 (/home/ubuntu/pset4/filter/filter+0x427fa9)
#1 0x4232b1 (/home/ubuntu/pset4/filter/filter+0x4232b1)
#2 0x7f7a4db1bb96 (/lib/x86_64-linux-gnu/libc.so.6+0x21b96)
#3 0x402dd9 (/home/ubuntu/pset4/filter/filter+0x402dd9)
UndefinedBehaviorSanitizer can not provide additional info.
==8771==ABORTING
知道这可能是什么吗?
您正在访问 image
二维数组的边界。
这种情况发生在几个方面。
缺点ide你的循环:
for (int i = 0; i < height; i++)
{
for (int j = 0; j < width; j++)
{
}
}
i
和 j
是可以分别从 0 和 height
以及从 0 和 width
.
变化的索引
但是对于这两个循环,您访问的都超出了这个限制。例如,如果 j = width-1
:
if ( j + 1 < width - 1 && j + 1 > 0)
{
div++;
}
else
{
image[i][j + 1].rgbtRed = 0;
image[i][j + 1].rgbtRed = 0;
image[i][j + 1].rgbtRed = 0;
}
第一个条件不会像 width-1+1 > width -1
那样为真,因此您最终会进入 else
部分,您将在其中访问
image[i][width].rgbtRed = 0;
那是越界!
每当 i = height-1
时都会发生同样的情况:诸如 image[i + 1][j]
的行将访问
image[height][j].rgbtRed = 0;
这也是越界的。
越界访问数组会导致未定义的行为,这就是您的消毒程序检测到的。
注意:虽然与您所要求的错误无关,但您可能还想更正
中的错误
image[i][j + 1].rgbtRed = 0;
image[i][j + 1].rgbtRed = 0;
image[i][j + 1].rgbtRed = 0;
以及整个功能的相似部分。请注意,只有 Red 级别受到影响(三次!);我想你打算影响 Green 和 Blue,而不是。
如何进行
为您实现整个功能超出了这个问题的范围,但我会尝试建议如何进行。
对于每个像素,您目前
- 计算不在图像边缘的元素(
div++
)
- 将不应影响平均值的元素设置为 0(实际上 超出范围 并导致您未定义的行为)
- 通过div
求和divide和divide周围所有元素的值(包括你设置为0的元素)
但是是什么迫使你对所有元素求和?只求那些真正有用的!您已经有一个正确的位置来执行此求和:这是您递增 div
.
的位置
类似的东西:
for (int i = 0; i < height; i++)
{
for (int j = 0; j < width; j++)
{
int div = 1;
int curRedSum = 0, curGReenSum = 0, curBlueSum = 0;
if ( j + 1 < width - 1 && j + 1 > 0)
{
div++;
curRedSum += image[i][j + 1].rgbtRed;
curGreenSum += image[i][j + 1].rgbtGreen;
curBlueSum += image[i][j + 1].rgbtBlue;
}
if ( i + 1 < height - 1 && i + 1 > 0)
{
div++;
curRedSum += image[i+1][j].rgbtRed;
curGreenSum += image[i+1][j].rgbtGreen;
curBlueSum += image[i+1][j].rgbtBlue;
}
/* ... */
float averageR = (float)(curRedSum / ( float )div );
float averageG = (float)(curGreenSum / ( float )div );
float averageB = (float)(curBlueSum / ( float )div );
image[i][j].rgbtRed = round(averageR); // Shouldn't this assignemnt be performed on a copy of the image?
image[i][j].rgbtGreen = round(averageG); // Shouldn't this assignemnt be performed on a copy of the image?
image[i][j].rgbtBlue = round(averageB); // Shouldn't this assignemnt be performed on a copy of the image?
}
}
免责声明:这个建议应该只是一个提示。我不保证这会在没有任何进一步调整的情况下编译和工作。
我运行正在编写以下代码
void blur(int height, int width, RGBTRIPLE image[height][width])
{
for (int i = 0; i < height; i++)
{
for (int j = 0; j < width; j++)
{
int div = 1;
if ( j + 1 < width - 1 && j + 1 > 0)
{
div++;
}
else
{
image[i][j + 1].rgbtRed = 0;
image[i][j + 1].rgbtRed = 0;
image[i][j + 1].rgbtRed = 0;
}
if ( i + 1 < height - 1 && i + 1 > 0)
{
div++;
}
else
{
image[i + 1][j].rgbtRed = 0;
image[i + 1][j].rgbtRed = 0;
image[i + 1][j].rgbtRed = 0;
}
if ( j + 1 < width - 1 && j + 1 > 0 && i + 1 < height - 1 && i + 1 > 0)
{
div++;
}
else
{
image[i + 1][j + 1].rgbtRed = 0;
image[i + 1][j + 1].rgbtRed = 0;
image[i + 1][j + 1].rgbtRed = 0;
}
if ( i - 1 < height - 1 && i - 1 > 0)
{
div++;
}
else
{
image[i - 1][j].rgbtRed = 0;
image[i - 1][j].rgbtRed = 0;
image[i - 1][j].rgbtRed = 0;
}
if ( i - 1 < height - 1 && i - 1 > 0 && j + 1 < width - 1 && j + 1 > 0)
{
div++;
}
else
{
image[i - 1][j + 1].rgbtRed = 0;
image[i - 1][j + 1].rgbtRed = 0;
image[i - 1][j + 1].rgbtRed = 0;
}
if ( j - 1 < width - 1 && j - 1 > 0)
{
div++;
}
else
{
image[i][j - 1].rgbtRed = 0;
image[i][j - 1].rgbtRed = 0;
image[i][j - 1].rgbtRed = 0;
}
if ( j - 1 < width - 1 && j - 1 > 0 && i + 1 < height - 1 && i + 1 > 0)
{
div++;
}
else
{
image[i + 1][j - 1].rgbtRed = 0;
image[i + 1][j - 1].rgbtRed = 0;
image[i + 1][j - 1].rgbtRed = 0;
}
if ( j - 1 < width - 1 && j - 1 > 0 && i - 1 < height - 1 && i - 1 > 0)
{
div++;
}
else
{
image[i - 1][j - 1].rgbtRed = 0;
image[i - 1][j - 1].rgbtRed = 0;
image[i - 1][j - 1].rgbtRed = 0;
}
int averageR = (float)(image[i][j].rgbtRed + image[i][j + 1].rgbtRed + image[i][j - 1].rgbtRed + image[i + 1][j].rgbtRed + image[i - 1][j].rgbtRed + image[i + 1][j + 1].rgbtRed + image[i + 1][j - 1].rgbtRed + image[i - 1][j + 1].rgbtRed + image[i + 1][j - 1].rgbtRed) / div;
int averageG = (float)(image[i][j].rgbtGreen + image[i][j + 1].rgbtGreen + image[i][j - 1].rgbtGreen + image[i + 1][j].rgbtGreen + image[i - 1][j].rgbtGreen + image[i + 1][j + 1].rgbtGreen + image[i + 1][j - 1].rgbtGreen + image[i - 1][j + 1].rgbtGreen + image[i + 1][j - 1].rgbtGreen) / div;
int averageB = (float)(image[i][j].rgbtBlue + image[i][j + 1].rgbtBlue + image[i][j - 1].rgbtBlue + image[i + 1][j].rgbtBlue + image[i - 1][j].rgbtBlue + image[i + 1][j + 1].rgbtBlue + image[i + 1][j - 1].rgbtBlue + image[i - 1][j + 1].rgbtBlue + image[i + 1][j - 1].rgbtBlue) / div;
image[i][j].rgbtRed = round(averageR);
image[i][j].rgbtGreen = round(averageG);
image[i][j].rgbtBlue = round(averageB);
}
}
return;
}
不幸的是,每次我尝试 运行 它的模糊部分时,它都会出现此消息:
UndefinedBehaviorSanitizer:DEADLYSIGNAL
==8771==ERROR: UndefinedBehaviorSanitizer: SEGV on unknown address 0x7f7a4ec2890a (pc 0x000000427faa bp 0x7ffd07cd9170 sp 0x7ffd07cd7560 T8771)
==8771==The signal is caused by a WRITE memory access.
#0 0x427fa9 (/home/ubuntu/pset4/filter/filter+0x427fa9)
#1 0x4232b1 (/home/ubuntu/pset4/filter/filter+0x4232b1)
#2 0x7f7a4db1bb96 (/lib/x86_64-linux-gnu/libc.so.6+0x21b96)
#3 0x402dd9 (/home/ubuntu/pset4/filter/filter+0x402dd9)
UndefinedBehaviorSanitizer can not provide additional info.
==8771==ABORTING
知道这可能是什么吗?
您正在访问 image
二维数组的边界。
这种情况发生在几个方面。
缺点ide你的循环:
for (int i = 0; i < height; i++)
{
for (int j = 0; j < width; j++)
{
}
}
i
和 j
是可以分别从 0 和 height
以及从 0 和 width
.
但是对于这两个循环,您访问的都超出了这个限制。例如,如果 j = width-1
:
if ( j + 1 < width - 1 && j + 1 > 0)
{
div++;
}
else
{
image[i][j + 1].rgbtRed = 0;
image[i][j + 1].rgbtRed = 0;
image[i][j + 1].rgbtRed = 0;
}
第一个条件不会像 width-1+1 > width -1
那样为真,因此您最终会进入 else
部分,您将在其中访问
image[i][width].rgbtRed = 0;
那是越界!
每当 i = height-1
时都会发生同样的情况:诸如 image[i + 1][j]
的行将访问
image[height][j].rgbtRed = 0;
这也是越界的。
越界访问数组会导致未定义的行为,这就是您的消毒程序检测到的。
注意:虽然与您所要求的错误无关,但您可能还想更正
中的错误image[i][j + 1].rgbtRed = 0;
image[i][j + 1].rgbtRed = 0;
image[i][j + 1].rgbtRed = 0;
以及整个功能的相似部分。请注意,只有 Red 级别受到影响(三次!);我想你打算影响 Green 和 Blue,而不是。
如何进行
为您实现整个功能超出了这个问题的范围,但我会尝试建议如何进行。
对于每个像素,您目前
- 计算不在图像边缘的元素(
div++
) - 将不应影响平均值的元素设置为 0(实际上 超出范围 并导致您未定义的行为)
- 通过div 求和divide和divide周围所有元素的值(包括你设置为0的元素)
但是是什么迫使你对所有元素求和?只求那些真正有用的!您已经有一个正确的位置来执行此求和:这是您递增 div
.
类似的东西:
for (int i = 0; i < height; i++)
{
for (int j = 0; j < width; j++)
{
int div = 1;
int curRedSum = 0, curGReenSum = 0, curBlueSum = 0;
if ( j + 1 < width - 1 && j + 1 > 0)
{
div++;
curRedSum += image[i][j + 1].rgbtRed;
curGreenSum += image[i][j + 1].rgbtGreen;
curBlueSum += image[i][j + 1].rgbtBlue;
}
if ( i + 1 < height - 1 && i + 1 > 0)
{
div++;
curRedSum += image[i+1][j].rgbtRed;
curGreenSum += image[i+1][j].rgbtGreen;
curBlueSum += image[i+1][j].rgbtBlue;
}
/* ... */
float averageR = (float)(curRedSum / ( float )div );
float averageG = (float)(curGreenSum / ( float )div );
float averageB = (float)(curBlueSum / ( float )div );
image[i][j].rgbtRed = round(averageR); // Shouldn't this assignemnt be performed on a copy of the image?
image[i][j].rgbtGreen = round(averageG); // Shouldn't this assignemnt be performed on a copy of the image?
image[i][j].rgbtBlue = round(averageB); // Shouldn't this assignemnt be performed on a copy of the image?
}
}
免责声明:这个建议应该只是一个提示。我不保证这会在没有任何进一步调整的情况下编译和工作。