_TypeError(类型'_InternalLinkedHashMap<String, dynamic>'不是类型'Iterable<dynamic>'的子类型)Flutter

_TypeError (type '_InternalLinkedHashMap<String, dynamic>' is not a subtype of type 'Iterable<dynamic>') Flutter

从 api 获取单个用户时,我遇到了标题中提到的上述错误,我的回复是

{"success":true,"data":{"id":4,"user_id":"4","email":"xyz@example.com","secondaryPhone":"+2515465465465"},"message":"User retrieved successfully."}

我的模型class

class UsersModel({this.id, this.user_id, this.email, this.secondaryPhone});

我的api调用如下

class UsersApi {
  Future<List<UsersModel>> fetchUsersById(String uId) async 
 {String singleUser = CallApi.url+CallApi.sinleUser+uId; 
   
 Map<String,String> headers =  
  { 'Accept' : 'application/json'};  
  var response = await http.get(singleUser ,headers:headers);  
       List<UsersModel> users= List<UsersModel>();
    if(response.statusCode == 200){
      var jsonData = jsonDecode(response.body);
      var data = jsonData["data"];
      for( var userr in data ) // error comes on this line
{        
UsersModel user = UsersModel(
id:item["id"].toString(),
user_id:item["user_id"].toString(),
email:item["email"].toString(),
secondaryPhone:item["secondaryPhone"].toString(),
);
 users.add(user);
      }
}
  return users;
}


}

感谢任何帮助。

您显示的 JSON 不包含任何列表。您暗示当您获取多个用户时,此代码工作正常,可能是因为 jsonData["data"] 在您获取多个用户时实际上返回 List

要解决这个问题,您应该检查 jsonData["data"] 的类型。如果它是 List 则执行您当前拥有的,如果不是,则以不同的方式处理它。

例如

Future<List<UsersModel>> fetchUsersById(String uId) async {
  String singleUser = CallApi.url+CallApi.sinleUser+uId;
   
 Map<String,String> headers =  
  { 'Accept' : 'application/json'};  
  var response = await http.get(singleUser ,headers:headers);  
       List<UsersModel> users= List<UsersModel>();
    if(response.statusCode == 200){
      var jsonData = jsonDecode(response.body);
      var data = jsonData["data"];

      //Handle data differently if it's a Map
      if(data is Map) {
        UsersModel user = UsersModel(
          id:item["id"].toString(),
          user_id:item["user_id"].toString(),
          email:item["email"].toString(),
          secondaryPhone:item["secondaryPhone"].toString(),
        );
        users.add(user);
        return users;
      }

      //Otherwise, do what you currently have
      for( var userr in data )
      {        
        UsersModel user = UsersModel(
          id:item["id"].toString(),
          user_id:item["user_id"].toString(),
          email:item["email"].toString(),
          secondaryPhone:item["secondaryPhone"].toString(),
        );
        users.add(user);
      }
  }
  return users;
}