计算来自不同数据源的方差 Oracle SQL

Question

我正在尝试根据从两个不同来源获得的数据创建一个差异列表。此数据包含一个日期、一系列参考和包含数字计数的列等。

这背后的想法是检查数据源 1 中的数据与数据源 2 中的数据是否具有相同的数值计数，然后记录每 5 分钟间隔的差异。

这里我有创建简化场景table和示例数据所需的代码

Create Table ABP_PROFILE 
(  ABP_DATE            Date          not Null, 
  ABP_SOURCE_UID      Number(10)  not Null, 
  ABP_REFERENCE_1     Varchar2(30)  not Null, 
  ABP_CHARGE          Number(18,6), 
  ABP_COUNT           Number(18)
);

insert into ABP_PROFILE (ABP_DATE, ABP_SOURCE_UID, ABP_REFERENCE_1, ABP_CHARGE, ABP_COUNT)
values (to_date('15-06-2015 00:05:00', 'dd-mm-yyyy hh24:mi:ss'), 1, 'Another Reference', 757.500000, 101);

insert into ABP_PROFILE (ABP_DATE, ABP_SOURCE_UID, ABP_REFERENCE_1, ABP_CHARGE, ABP_COUNT)
values (to_date('15-06-2015 00:05:00', 'dd-mm-yyyy hh24:mi:ss'), 1, 'Some Reference', 2954.000000, 211);

insert into ABP_PROFILE (ABP_DATE, ABP_SOURCE_UID, ABP_REFERENCE_1, ABP_CHARGE, ABP_COUNT)
values (to_date('15-06-2015 00:05:00', 'dd-mm-yyyy hh24:mi:ss'), 2, 'Another Reference', 757.500000, 101);

insert into ABP_PROFILE (ABP_DATE, ABP_SOURCE_UID, ABP_REFERENCE_1, ABP_CHARGE, ABP_COUNT)
values (to_date('15-06-2015 00:05:00', 'dd-mm-yyyy hh24:mi:ss'), 2, 'Some Reference', 2954.000000, 211);

insert into ABP_PROFILE (ABP_DATE, ABP_SOURCE_UID, ABP_REFERENCE_1, ABP_CHARGE, ABP_COUNT)
values (to_date('15-06-2015 00:10:00', 'dd-mm-yyyy hh24:mi:ss'), 1, 'Another Reference', 5300.250000, 191);

insert into ABP_PROFILE (ABP_DATE, ABP_SOURCE_UID, ABP_REFERENCE_1, ABP_CHARGE, ABP_COUNT)
values (to_date('15-06-2015 00:10:00', 'dd-mm-yyyy hh24:mi:ss'), 1, 'Some Reference', 9568.000000, 208);

insert into ABP_PROFILE (ABP_DATE, ABP_SOURCE_UID, ABP_REFERENCE_1, ABP_CHARGE, ABP_COUNT)
values (to_date('15-06-2015 00:10:00', 'dd-mm-yyyy hh24:mi:ss'), 2, 'Another Reference', 5300.250000, 5555);

insert into ABP_PROFILE (ABP_DATE, ABP_SOURCE_UID, ABP_REFERENCE_1, ABP_CHARGE, ABP_COUNT)
values (to_date('15-06-2015 00:10:00', 'dd-mm-yyyy hh24:mi:ss'), 2, 'Some Reference', 1111.000000, 208);

我在这里创建了一个 BASIC SQL 查询来了解我想做什么。

With A_DATA As (
  Select  ABP_DATE              As A_DATE,
          ABP_REFERENCE_1       As A_REFERENCE_1, 
          ABP_CHARGE            As A_CHARGE, 
          ABP_COUNT             As A_COUNT
  From    ABP_PROFILE           
  Where   ABP_SOURCE_UID = 1
), B_DATA As (
  Select  ABP_DATE              As B_DATE,
          ABP_REFERENCE_1       As B_REFERENCE_1, 
          ABP_CHARGE            As B_CHARGE, 
          ABP_COUNT             As B_COUNT
  From    ABP_PROFILE           
  Where   ABP_SOURCE_UID = 2
)
Select  A_DATE,
        A_REFERENCE_1,
        B_CHARGE  - A_CHARGE  As ChargeDifference,
        B_COUNT   - A_COUNT   As CountDifference
From    A_DATA,
        B_DATA
Where   A_DATE        = B_DATE
And     A_REFERENCE_1 = B_REFERENCE_1
;

这会根据两个数据源的日期和引用进行联接。我需要一个更加通用的解决方案，如果缺少一侧的数据，还需要显示差异，是的，可以为此使用完整的外部联接，但我想探索其他选项。

我一直在研究分析函数，我确信那里有一个可以做我想做的事情。我想知道是否有任何 Oracle SQL 专家有任何想法可以在这里提供帮助。

仅供参考，我是运行 11gR2 Enterprise

Answer 1

带有 FULL JOIN 的解决方案似乎更具可读性，但如果您搜索替代方案 - 在这里 - 具有函数 lag() 和 lead():

with data as (
  select abp_date dt, abp_source_uid id, abp_reference_1 ref, 
      abp_charge charge, abp_count cnt,
      lag(abp_source_uid) over (partition by abp_date, abp_reference_1 
                                order by abp_source_uid) lgid,
      lead(abp_charge)    over (partition by abp_date, abp_reference_1 
                                order by abp_source_uid) ldcharge,
      lead( abp_count)    over (partition by abp_date, abp_reference_1 
                                order by abp_source_uid) ldcnt
    from abp_profile a)
select dt, ref, 
    case when id = 1 then nvl(ldcharge, 0) - charge else charge end chrg_diff,
    case when id = 1 then nvl(ldcnt, 0) - cnt else cnt end cnt_diff
  from data
  where id = 1 or id = 2 and lgid is null;

... 并且您修改后的查询已转换为 full join 版本，我将其用于比较结果：

With A_DATA As (
  Select  ABP_DATE              As A_DATE,
          ABP_REFERENCE_1       As A_REFERENCE_1, 
          ABP_CHARGE            As A_CHARGE, 
          ABP_COUNT             As A_COUNT
  From    ABP_PROFILE           
  Where   ABP_SOURCE_UID = 1
), B_DATA As (
  Select  ABP_DATE              As B_DATE,
          ABP_REFERENCE_1       As B_REFERENCE_1, 
          ABP_CHARGE            As B_CHARGE, 
          ABP_COUNT             As B_COUNT
  From    ABP_PROFILE           
  Where   ABP_SOURCE_UID = 2
)
Select  nvl(A_DATE, b_date) dt,
        nvl(A_REFERENCE_1, b_reference_1) ref,
        nvl(B_CHARGE, 0) - nvl(A_CHARGE, 0)  As Chrg_Diff,
        nvl(B_COUNT, 0)   - nvl(A_COUNT, 0)  As Cnt_Diff
From    A_DATA 
full join B_DATA on A_DATE = B_DATE and A_REFERENCE_1 = B_REFERENCE_1;

SQLFiddle

两个查询给出了相同的结果。在示例中，我添加了两行来展示如何处理丢失的数据。这里我使用了 nvl(..., 0) 但当然你可以保留空值或添加列来告知这种情况。

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