使用 Matplotlib 绘制坐标会扭曲底图

Question

我正在尝试使用 Geopandas 和 Matplotlib 在地图上显示商店的空间分布。

问题： 当我绘制图钉时，底图会变形。这是绘制引脚之前和 .

之后的示例

问题： 这种扭曲的根源是什么？我该如何预防？

import pandas as pd
import geopandas as gpd
import matplotlib.pyplot as plt
from shapely.geometry import Polygon

# Creating the simplified polygon
latitude = [60.41125, 59.99236, 59.99236]
longitude = [24.66917, 24.66917, 25.36972]
geometry = Polygon(zip(longitude, latitude))
polygon = gpd.GeoDataFrame(index=[0], crs = 'epsg:4326', geometry=[geometry]) 

# ploting  the basemap
ax = polygon.plot(color="#3791CB")

# Dict of sample coordinates
coordinates = {"latitude": ["60.193141", "60.292777", "60.175053", "60.163187", "60.245272", "60.154392", "60.182906"],
"longitude": ["24.934214", "24.969730", "24.831068", "24.739044", "24.860983", "24.884773", "24.959175"]}

# Creating a dataframe from coordinates
df = pd.DataFrame(coordinates)

# Creating the GeoDataFrame
shops = gpd.GeoDataFrame(coordinates, geometry=gpd.points_from_xy(df.longitude, df.latitude))

# Plotting office coordinates
shops.plot(ax=ax, color="red", markersize = 20, zorder=2)

# adding grid
plt.grid(linestyle=":", color='grey')

plt.show()

谢谢！

Answer 1

你的地图和图钉有不同的参考系统..

创建第一个 GeoDataFrame 时指定其坐标参考系 (crs = 'epsg:4326')。当您为商店坐标创建地理数据框时，您不需要。这就是失真的来源..

这应该可以解决：

shops = gpd.GeoDataFrame(
        coordinates, 
        geometry = gpd.points_from_xy(
              df.longitude, 
              df.latitude), 
              crs = "EPSG:4326" 
              )
        )

干杯！

使用 Matplotlib 绘制坐标会扭曲底图

Plotting coordinates with Matplotlib is distorting the base-map

python

matplotlib

geopandas