不使用结构在 C 中显示所有数据

Question

所以我有这个简单的 C 程序，我正在努力帮助我理解结构。没有什么太复杂的了。但是，当它到达应该显示数据的位置时，它只显示了部分数据。该程序要求用户提供名字和姓氏，然后是金额。然后它应该显示名字和姓氏，以及金额。它不显示姓氏。我确信这可能很简单，但我不确定我在这里遗漏了什么。

代码如下：

    #include <stdio.h>
    #include <stdlib.h>

    #define NAMESIZE 30 

    struct data{
         float amount;
         char firstName[NAMESIZE];
         char lastName [NAMESIZE];
    }record;

    int main()
    {
         printf("\nEnter the donor's first and last names \n");
         printf("Separate names by a space: ");
         scanf("%s, %s", record.firstName, record.lastName);
 
         char c;
         while ( (c = getchar()) != '\n' && c != EOF )
              {
         }
 
         // At this point the program does not work correctly
         // It will just print the first name not the last name
         printf("\nEnter the donation amount: ");
         scanf("%f", &record.amount);

         // Display the information
         printf("\nDonor %s %s gave $%.2f \n", record.firstName, record.lastName, record.amount);

    return 0;
     }

如有任何建议，我们将不胜感激。谢谢

一旦我去掉了第一次 scanf 调用中的多余逗号，它就起作用了。这是已更正的行：

             scanf("%s %s", record.firstName, record.lastName);

我在两个 %s 之间用了一个逗号，这是不正确的。

Answer 1

或者可以使用具有缓冲区溢出保护的 fgets 并使用 strtok 拆分间距

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

    #define NAMESIZE 30 

    struct data{
         float amount;
         char firstName[NAMESIZE];
         char lastName [NAMESIZE];
    }record;

    int main()
    {
        char *name = malloc(NAMESIZE);
        if (name == NULL) {
        printf("No memory\n");
        return 1;
        }

         printf("\nEnter the donor's first and last names \n");
         printf("Separate names by a space: ");
         //scanf("%s, %s", record.firstName, record.lastName);
         fgets(name, NAMESIZE, stdin);

        if ((strlen(name) > 0) && (name[strlen (name) - 1] == '\n'))
            name[strlen (name) - 1] = '[=10=]';

        //split name
    int init_size = strlen(name);
    char delim[] = " ";

    char *ptr = strtok(name, delim);
    int idx = 0;
    while(ptr != NULL)
    {
        printf("%d '%s'\n",idx, ptr);
                if(idx == 0){
          strcpy(record.firstName, ptr);
                }
                else{
                  strcpy(record.lastName, ptr);
        }
        ptr = strtok(NULL, delim);
        idx += 1;
    }

     /*
         char c;
         while ( (c = getchar()) != '\n' && c != EOF )
              {
         }
         */
         // At this point the program does not work correctly
         // It will just print the first name not the last name
         printf("\nEnter the donation amount: ");
         scanf("%f", &record.amount);

         // Display the information
         printf("\nDonor %s %s gave $%.2f \n", record.firstName, record.lastName, record.amount);

    free(name);
    return 0;
     }

不使用结构在 C 中显示所有数据

Not displaying all data in C using struct

c

io

printf

struct