Symfony 使用 "NOT IN" 连接 DQL 表达式

Question

我正在使用 Symfony2，我正在尝试获取一组与指定客户端无关的语言。

我有一个 Client 表示客户端的实体，ClientLanguage 具有以下结构：

id_menu_language 主键
language 与语言实体的关联
client 与客户实体的关联
sequence 表示语言的显示顺序（此处未使用）

和Language实体。

要获取与客户端无关的一组语言，我想按以下方式进行：

获取客户端已经关联的语言（我在 $clientLanguagesDQL 变量中获取正确的 DQL）
检索所有可用语言的列表
从该列表中排除所有已经关联到客户端的语言（通过使用 NOT IN (...) ）。

这是我写的函数来实现：

<?php

namespace AppBundle\Repository;

use AppBundle\Entity\Client;
use Doctrine\ORM\EntityRepository;
use Doctrine\ORM\Query\Expr\Join;

class ClientRepository extends EntityRepository
{

    /**
     * @param $client Client to check
     * @return array
     */
    public function getLanguagesNotAssociatedToClient($client)
    {
        $qb = $this->getEntityManager()->createQueryBuilder();

        $clientLanguagesDQL = $qb
            ->select('lang')
            ->from('AppBundle:Language', 'lang')
            ->join('AppBundle:ClientLanguage', 'languages_assoc', Join::WITH, 'languages_assoc.language = lang')
            ->join('AppBundle:Client', 'client', Join::WITH, 'languages_assoc.client = client')
            ->where('client.idClient = :client_id')
            ->getQuery()
            ->getDQL();

        $languages = $qb->select('language')
            ->from('AppBundle:Language', 'language')
            ->where($qb->expr()->notIn('language', $clientLanguagesDQL))
            ->setParameter('client_id', $client->getIdClient())
            ->getQuery()
            ->getResult();

        return $languages;

    }
}

然而，当我运行这个时，Symfony 抱怨 : [Semantical Error] line 0, col 293 near 'lang INNER JOIN': Error: 'lang' is already defined. 它也告诉我有一个 QueryException，它向我显示了以下查询：

SELECT language 
FROM AppBundle:Language lang 
    INNER JOIN AppBundle:ClientLanguage languages_assoc 
        WITH languages_assoc.language = lang 
    INNER JOIN AppBundle:Client client 
        WITH languages_assoc.client = client, AppBundle:Language language WHERE language NOT IN(
    SELECT lang 
    FROM AppBundle:Language lang 
        INNER JOIN AppBundle:ClientLanguage languages_assoc 
            WITH languages_assoc.language = lang 
        INNER JOIN AppBundle:Client client 
            WITH languages_assoc.client = client 
    WHERE client.idClient = :client_id
)

而这绝对不是我想做的。为什么出现 AppBundle:ClientLanguage 和 AppBundle:Client 的两个连接？我只在我的第一个子查询中使用这个关联。

如果有帮助，当我运行这个：

    $clientLanguagesDQL = $qb
        ->select('lang')
        ->from('AppBundle:Language', 'lang')
        ->join('AppBundle:ClientLanguage', 'languages_assoc', Join::WITH, 'languages_assoc.language = lang')
        ->join('AppBundle:Client', 'client', Join::WITH, 'languages_assoc.client = client')
        ->where('client.idClient = :client_id')
        ->getQuery()
        ->getDQL();

这是存储在$clientLanguageDQL中返回的DQL:

SELECT lang 
FROM AppBundle:Language lang 
    INNER JOIN AppBundle:ClientLanguage languages_assoc 
        WITH languages_assoc.language = lang 
    INNER JOIN AppBundle:Client client 
        WITH languages_assoc.client = client 
WHERE client.idClient = :client_id

这个查询有什么问题？

Answer 1

我的错误非常愚蠢，我所要做的就是为每个查询创建一个新的查询构建器，而不是重复使用第一个：

    $qb1 = $this->getEntityManager()->createQueryBuilder();

    $clientLanguagesDQL = $qb1
        ->select('lang')
        ->from('AppBundle:Language', 'lang')
        ->join('AppBundle:ClientLanguage', 'languages_assoc', Join::WITH, 'languages_assoc.language = lang')
        ->join('AppBundle:Client', 'client', Join::WITH, 'languages_assoc.client = client')
        ->where('client.idClient = :client_id')
        ->getQuery()
        ->getDQL();

    $qb2 = $this->getEntityManager()->createQueryBuilder();
    $languages = $qb2->select('language')
        ->from('AppBundle:Language', 'language')
        ->where($qb2->expr()->notIn('language', $clientLanguagesDQL))
        ->setParameter('client_id', $client->getIdClient())
        ->getQuery()
        ->getResult();

    return $languages;

Symfony 使用 "NOT IN" 连接 DQL 表达式

Symfony joining DQL expressions with "NOT IN"

php

dql

symfony

doctrine-orm