Codeigniter 4 未定义索引：user_id

Question

我正在尝试显示“加入”结果并且只想为用户 table 显示 user_id、用户名、电子邮件一次，即使另一个 table 上有很多记录 table，所以我尝试制作如下查询生成器：

Table users                          | Table add_game
                                     |
user_id | username | email           | game_id | user_id | ign    | acc_id

1       | userA    | userA@email.com | 1       | 1       | ignA   | accA
2       | userB    | userB@gmail.com | 2       | 1       | ignB   | accB
                                     | 1       | 2       | ignB   | accB
                                     | 3       | 2       | ignD   | accD

型号：

<?php namespace App\Models;

use CodeIgniter\Database\ConnectionInterface;

class LoginModel{
    
    protected $db;

    public function __construct(ConnectionInterface &$db){
        $this->db =& $db;
    }


    public function login(string $str)
    {


        return $this->db->table('users')
                        
                        ->groupStart()
                            ->where('username', $str)
                            ->orWhere('email', $str)
                        ->groupEnd()
                        
                        ->join('add_game', 'add_game.user_id = users.user_id')
                        //->distinct('users.user_id')
                        //->select(("GROUP_CONCAT(game_id, ign, acc_id) AS userdata"))
                        ->get()
                        ->getResultArray();
    }
    
}

控制器：

public function login()
    {

        $data = [];
        helper(['form']);
        
        $validation =  \Config\Services::validation();

        $db = db_connect();
        $model = new LoginModel($db);
        $user = $model->login($this->request->getVar('userlogin'));

        $this->setUserSession($user);
        
            echo view('templates/header', $data);
            echo view('account/login', $data);
            echo view('templates/footer', $data);
        
        
    }


    private function setUserSession($user){
        $data = [
            'user_id' => $user['user_id'],
            'username' => $user['username'],
            'email' => $user['email'],
            'firstname' => $user['firstname'],
            'lastname' => $user['lastname'],
            'dob' => $user['dob'],
            'country' => $user['country'],
            'country_code' => $user['c_code'],
            'contact' => $user['contact'],
            'game_id' => $user['game_id'],
            'ign' => $user['ign'],
            'acc_id' => $user['acc_id'],
            'isLoggedIn' => true
        ];
        
        session()->set($data);
        return true;
    }

但现在我得到

Undefined index: user_id

错误信息。以前，当我在没有查询生成器的情况下登录时没有问题或错误：

public function login(string $str, string $fields, array $data)
    {
        return $this->where('username', $data['userlogin'])->orWhere('email', $data['userlogin'])
                                  ->first();
    }

如何解决这个错误？

Answer 1

根据您的评论（图片），您的数组如下所示：

Array
(
  [0]=>Array
    (
      [user_id]=>1,
      [user_name]=>'test',
      //etc.
    )
)

你得到了

Undefined index: user_id

错误消息，因为在使用 'user_id' => $user['user_id']

时错误地寻址数组

正确的方法是添加要检索的索引，例如：

$this->setUserSession($user[0]);   // where 0 can be changed to the index you pretend

现在数组被展平了，'user_id' => $user['user_id'] 不再抛出错误。

Codeigniter 4 未定义索引：user_id

Codeigniter 4 Undefined index: user_id

query-builder

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