指针给出整个数组而不是 C++ RayLib 中的一个字符
Pointer gives whole array instead of one character in C++ RayLib
我是 C++ 的新手,决定从使用 RayLib 作为图形引擎制作井字游戏开始。
下面的代码设置一个屏幕,绘制网格并检查输入。
我正在处理的部分是在单击的字段中显示 X 或 O。
我终于得到了绘制文本的程序,但它似乎绘制了整个数组而不是一个字母。
#include "raylib.h"
#include <string.h>
#include <stdio.h>
#include <math.h>
int main(void)
{
//INITIALIZE//
int screenWidth = 750;
int screenHeight = 750;
char matrix[9] = {'E', 'E', 'E', 'E', 'E', 'E', 'E', 'E', 'E'};
char currentPlayer = 'X';
InitWindow(screenWidth, screenHeight, "raylib [core] example - basic window");
SetTargetFPS(60);
while (!WindowShouldClose())
{
//INPUT//
if (IsMouseButtonPressed(MOUSE_LEFT_BUTTON)) {
int mouseX = GetMouseX();
int mouseY = GetMouseY();
double x = floor(mouseX/250);
double y = floor(mouseY/250);
int index = x + 3*y;
matrix[index] = currentPlayer;
currentPlayer = (currentPlayer == 'X') ? 'O' : 'X';
}
//DRAWING//
BeginDrawing();
ClearBackground(WHITE);
for (int i = 1; i < 3; i++) {
int num = i*250;
DrawLine(num, 0, num, screenWidth, LIGHTGRAY);
DrawLine(0, num, screenHeight, num, LIGHTGRAY);
}
//Code I was working on
for (int i = 0; i < 9; i++) {
if (matrix[i] != 'E') {
int textX = 115 + i*250 - (i%3)*750;
int textY = 115 + (i%3)*250;
char text = matrix[i];
DrawText(&text, textX, textY, 20, LIGHTGRAY); //The problem is here
}
}
EndDrawing();
}
CloseWindow();
return 0;
}
当我单击左上角的单元格绘制 X 时,它绘制的是 'XXEEEEEEEE0?D'。
有谁知道如何从数组中只绘制一个字符?
提前致谢!
C-style 字符串以空字符 ([=14=]
) 结尾,因此您必须添加该字符,或者读取 out-of-bounds 并调用 undefine behavior.
因此,
char text = matrix[i];
应该是
char text[] = {matrix[i], '[=11=]'};
和
DrawText(&text, textX, textY, 20, LIGHTGRAY);
应该是
DrawText(text, textX, textY, 20, LIGHTGRAY);
(删除text
前的&
)
DrawText()
需要一个 null-terminated 字符串作为输入,但您给它的是一个 char
字符串。改变这个:
char text = matrix[i];
DrawText(&text, ...);
为此:
char text[2] = {matrix[i], '[=11=]'};
DrawText(text, ...);
你可以这样做:
char text = matrix[i];
char shortenedText[2] = {0, 0};
shortenedText[0] = text;
DrawText(shortenedText, textX, textY, 20, LIGHTGRAY); //The problem is here
基本上只用一个字符构建一个非常小的字符串。
我是 C++ 的新手,决定从使用 RayLib 作为图形引擎制作井字游戏开始。 下面的代码设置一个屏幕,绘制网格并检查输入。 我正在处理的部分是在单击的字段中显示 X 或 O。 我终于得到了绘制文本的程序,但它似乎绘制了整个数组而不是一个字母。
#include "raylib.h"
#include <string.h>
#include <stdio.h>
#include <math.h>
int main(void)
{
//INITIALIZE//
int screenWidth = 750;
int screenHeight = 750;
char matrix[9] = {'E', 'E', 'E', 'E', 'E', 'E', 'E', 'E', 'E'};
char currentPlayer = 'X';
InitWindow(screenWidth, screenHeight, "raylib [core] example - basic window");
SetTargetFPS(60);
while (!WindowShouldClose())
{
//INPUT//
if (IsMouseButtonPressed(MOUSE_LEFT_BUTTON)) {
int mouseX = GetMouseX();
int mouseY = GetMouseY();
double x = floor(mouseX/250);
double y = floor(mouseY/250);
int index = x + 3*y;
matrix[index] = currentPlayer;
currentPlayer = (currentPlayer == 'X') ? 'O' : 'X';
}
//DRAWING//
BeginDrawing();
ClearBackground(WHITE);
for (int i = 1; i < 3; i++) {
int num = i*250;
DrawLine(num, 0, num, screenWidth, LIGHTGRAY);
DrawLine(0, num, screenHeight, num, LIGHTGRAY);
}
//Code I was working on
for (int i = 0; i < 9; i++) {
if (matrix[i] != 'E') {
int textX = 115 + i*250 - (i%3)*750;
int textY = 115 + (i%3)*250;
char text = matrix[i];
DrawText(&text, textX, textY, 20, LIGHTGRAY); //The problem is here
}
}
EndDrawing();
}
CloseWindow();
return 0;
}
当我单击左上角的单元格绘制 X 时,它绘制的是 'XXEEEEEEEE0?D'。 有谁知道如何从数组中只绘制一个字符?
提前致谢!
C-style 字符串以空字符 ([=14=]
) 结尾,因此您必须添加该字符,或者读取 out-of-bounds 并调用 undefine behavior.
因此,
char text = matrix[i];
应该是
char text[] = {matrix[i], '[=11=]'};
和
DrawText(&text, textX, textY, 20, LIGHTGRAY);
应该是
DrawText(text, textX, textY, 20, LIGHTGRAY);
(删除text
前的&
)
DrawText()
需要一个 null-terminated 字符串作为输入,但您给它的是一个 char
字符串。改变这个:
char text = matrix[i];
DrawText(&text, ...);
为此:
char text[2] = {matrix[i], '[=11=]'};
DrawText(text, ...);
你可以这样做:
char text = matrix[i];
char shortenedText[2] = {0, 0};
shortenedText[0] = text;
DrawText(shortenedText, textX, textY, 20, LIGHTGRAY); //The problem is here
基本上只用一个字符构建一个非常小的字符串。