.contains() 不适用于 BufferedReader
.contains() not working with BufferedReader
我正在尝试创建一个程序来检查文件并在行中包含单词“TRUE”时将行打印回给我
这是文件内容
TRUE,TRUE
FALSE,TRUE
FALSE,FALSE
TRUE,FALSE
TRUE,TRUE
TRUE,FALSE
这是程序
public static void main(String[] args) {
// TODO Auto-generated method stub
BufferedReader reader;
try {
reader = new BufferedReader(new FileReader(
"C:\Users\tree3\Desktop\Programming\file.txt"));
String line = reader.readLine();
while (line != null) {
if(line.contains("TRUE")) {
System.out.println(line);
// read next line
line = reader.readLine();
} else {
System.out.println("false");
}
}
reader.close();
} catch (IOException e) {
e.printStackTrace();
}
}
程序只是无限期地打印 false
这是为什么?
public static void main(String[] args) {
try (BufferedReader reader = new BufferedReader(new FileReader("C:\Users\tree3\Desktop\Programming\file.txt"))) {
String line = reader.readLine();
while (line != null) {
if (line.contains("TRUE")) {
System.out.println(line);
} else {
System.out.println("false");
}
// read next line
line = reader.readLine();
}
} catch (IOException e) {
e.printStackTrace();
}
}
不要阅读 if 语句中的下一行。如果 if 语句不正确怎么办?你永远不会继续前进并无限期地卡在那条线上。
使用try-with-resources(Java7+)不用担心关闭资源
清洁工(Java 8 岁以上):
try (BufferedReader reader = new BufferedReader(new FileReader("C:\Users\tree3\Desktop\Programming\file.txt"))) {
reader.lines().forEach(line -> System.out.println(line.contains("TRUE")));
} catch (IOException e) {
e.printStackTrace();
}
我正在尝试创建一个程序来检查文件并在行中包含单词“TRUE”时将行打印回给我
这是文件内容
TRUE,TRUE
FALSE,TRUE
FALSE,FALSE
TRUE,FALSE
TRUE,TRUE
TRUE,FALSE
这是程序
public static void main(String[] args) {
// TODO Auto-generated method stub
BufferedReader reader;
try {
reader = new BufferedReader(new FileReader(
"C:\Users\tree3\Desktop\Programming\file.txt"));
String line = reader.readLine();
while (line != null) {
if(line.contains("TRUE")) {
System.out.println(line);
// read next line
line = reader.readLine();
} else {
System.out.println("false");
}
}
reader.close();
} catch (IOException e) {
e.printStackTrace();
}
}
程序只是无限期地打印 false
这是为什么?
public static void main(String[] args) {
try (BufferedReader reader = new BufferedReader(new FileReader("C:\Users\tree3\Desktop\Programming\file.txt"))) {
String line = reader.readLine();
while (line != null) {
if (line.contains("TRUE")) {
System.out.println(line);
} else {
System.out.println("false");
}
// read next line
line = reader.readLine();
}
} catch (IOException e) {
e.printStackTrace();
}
}
不要阅读 if 语句中的下一行。如果 if 语句不正确怎么办?你永远不会继续前进并无限期地卡在那条线上。
使用try-with-resources(Java7+)不用担心关闭资源
清洁工(Java 8 岁以上):
try (BufferedReader reader = new BufferedReader(new FileReader("C:\Users\tree3\Desktop\Programming\file.txt"))) {
reader.lines().forEach(line -> System.out.println(line.contains("TRUE")));
} catch (IOException e) {
e.printStackTrace();
}