array_merge 不适用于 2 个特殊的 json 数组

Question

有 2 个 json 数组，需要合并它们，但 array_merge 不起作用
我已经搜索并找到了可以真正与 array_merge

合并的 json 数组

这是我的 json 数据，在单独的文件中可用：

{
  "J": [
    {
      "a": "BAAB1",
      "b": "English"
    },
    {
      "a": "BAAB2",
      "b": "1"
    },
    {
      "a": "BAAB3",
      "b": "L"
    },
    {
      "a": "BAAB4",
      "b": "Test1 ..."
    },
    {
      "a": "BAAB5",
      "b": "Test2 ..."
    },
    {
      "a": "BAAB6",
      "b": "Test3 ..."
    }
  ]
}

并且：

{
  "J": [
    {
      "a": "BAAR1",
      "b": "T1"
    },
    {
      "a": "BAAR2",
      "b": "1"
    },
    {
      "a": "BAAR3",
      "b": "111111"
    },
    {
      "a": "BAAR4",
      "b": "3"
    },
    {
      "a": "BAAR5",
      "b": "3"
    },
    {
      "a": "BAAR6",
      "b": "222222"
    }
  ]
}

我从服务器上的路径读取文件，然后对每个读取文件使用 json_decode，然后使用 array_merge
我认为我的 json 数组 ("J"[=37=]) 的名称造成了问题

这是我的代码：

// $mLanguageFileName = $mClass_GeneralFunctions_General->GetStringBetween($mReadFile,"^^^","^^^^"); $mLanguageFile_Address = $ServerRoot_base.'/LAN/'.$mLanguageFileName.'.json'; $mClass_GeneralFunctions_FileFunctions = new GeneralFunctions_FileFunctions(); $mJSONFile_Language_C = $mClass_GeneralFunctions_FileFunctions->ReadFile($mLanguageFile_Address); // $mThemeFileName_M0 = $mClass_GeneralFunctions_General->GetStringBetween($mReadFile,"^^^^","^^^^^"); $mThemeFile_M0_Address = $ServerRoot_base.'/M0T/'.$mThemeFileName_M0.'/'.$mThemeFileName_M0.'.json'; $mClass_GeneralFunctions_FileFunctions = new GeneralFunctions_FileFunctions(); $mJSONFile_M0_C = $mClass_GeneralFunctions_FileFunctions->ReadFile($mThemeFile_M0_Address); // $mJsonArr_M0_C = json_decode($mJSONFile_M0_C, true); $mJsonArr_Language_C = json_decode($mJSONFile_Language_C, true); echo "\n\nmerge ... "; $L = sizeof($mJsonArr_M0_C["J"]); for ($i = 0; $i< $L; $i++) { echo "\n\nmJsonArr_M0_C i = {$i} "; echo "\nmJsonArr_M0_C a = {$mJsonArr_M0_C["J"][$i]["a"]} "; echo "\nmJsonArr_M0_C b = {$mJsonArr_M0_C["J"][$i]["b"]} "; } $L = sizeof($mJsonArr_Language_C["J"]); for ($i = 0; $i< $L; $i++) { echo "\n\nmJsonArr_Language_C i = {$i} "; echo "\nmJsonArr_Language_C a = {$mJsonArr_Language_C["J"][$i]["a"]} "; echo "\nmJsonArr_Language_C b = {$mJsonArr_Language_C["J"][$i]["b"]} "; } $mJsonArr_C_LanguageM0 = array_merge($mJsonArr_Language_C, $mJsonArr_M0_C); for ($i = 0; $i< sizeof($mJsonArr_C_LanguageM0["J"]); $i++) { echo "\n\nmJsonArr_C_LanguageM0 i = {$i} "; echo "\nmJsonArr_C_LanguageM0 a = {$mJsonArr_C_LanguageM0["J"][$i]["a"]} "; echo "\nmJsonArr_C_LanguageM0 b = {$mJsonArr_C_LanguageM0["J"][$i]["b"]} "; }

每个 json 数组的数据确实被回显，但合并数据只是 array_merge 中的第二个 json 数组($mJsonArr_M0_C)

我该如何解决这个问题？

Answer 1

这就是 array_merge 的工作方式：documentation 状态：

If the input arrays have the same string keys, then the later value for that key will overwrite the previous one.

像“J”这样的键就是这种情况：它是一个字符串键。

在您提供的案例中，array_merge_recursive 可以完成工作。例如：

$a = json_decode('{ "J": [{ "a": "BAAB1", "b": "English" }] }', true);
$b = json_decode('{ "J": [{ "a": "BAAR1", "b": "T1" }] }', true);
$merged = array_merge_recursive($a, $b);

array_merge 不适用于 2 个特殊的 json 数组

array_merge does not work for 2 special json arrays

php

array-merge