当第一个不总是 returns 特定行的值时,如何将一个 select 与另一个连接?
How to join one select with another when the first one not always returns a value for specific row?
我有一个复杂的查询来检索一些结果:
EDITED QUERY(添加了 UNION ALL):
SELECT t.*
FROM (
SELECT
dbo.Intervencao.INT_Processo, analista,
ETS.ETS_Sigla, ATC.ATC_Sigla, PAT.PAT_Sigla, dbo.Assunto.SNT_Peso,
CASE
WHEN ETS.ETS_Sigla = 'PE' AND (PAT.PAT_Sigla = 'LIB' OR PAT.PAT_Sigla = 'LBR') THEN (0.3*SNT_Peso)
WHEN ETS.ETS_Sigla = 'CD' THEN (0.3*SNT_Peso)*0.3
ELSE SNT_Peso
END AS PESOAREA,
CASE
WHEN a.max_TEA_FimTarefa IS NULL THEN a.max_TEA_InicioTarefa
ELSE a.max_TEA_FimTarefa
END AS DATA_INICIO_TERMINO,
ROW_NUMBER() OVER (PARTITION BY ATC.ATC_Sigla, a.SRV_Id ORDER BY TEA_FimTarefa DESC) AS seqnum
FROM dbo.Tarefa AS t
INNER JOIN (
SELECT
MAX(dbo.TarefaEtapaAreaTecnica.TEA_InicioTarefa) AS max_TEA_InicioTarefa,
MAX (dbo.TarefaEtapaAreaTecnica.TEA_FimTarefa) AS max_TEA_FimTarefa,
dbo.Pessoa.PFJ_Descri AS analista, dbo.AreaTecnica.ATC_Id, dbo.Tarefa.SRV_Id
FROM dbo.TarefaEtapaAreaTecnica
LEFT JOIN dbo.Tarefa ON dbo.TarefaEtapaAreaTecnica.TRF_Id = dbo.Tarefa.TRF_Id
LEFT JOIN dbo.AreaTecnica ON dbo.TarefaEtapaAreaTecnica.ATC_Id = dbo.AreaTecnica.ATC_Id
LEFT JOIN dbo.ServicoAreaTecnica ON dbo.TarefaEtapaAreaTecnica.ATC_Id = dbo.ServicoAreaTecnica.ATC_Id
AND dbo.Tarefa.SRV_Id = dbo.ServicoAreaTecnica.SRV_Id
INNER JOIN dbo.Pessoa ON dbo.Pessoa.PFJ_Id = dbo.ServicoAreaTecnica.PFJ_Id_Analista
GROUP BY dbo.AreaTecnica.ATC_Id, dbo.Tarefa.SRV_Id, dbo.Pessoa.PFJ_Descri
) AS a ON t.SRV_Id = a.SRV_Id
INNER JOIN dbo.TarefaEtapaAreaTecnica AS TarefaEtapaAreaTecnica_1 ON
t.TRF_Id = TarefaEtapaAreaTecnica_1.TRF_Id
AND a.ATC_Id = TarefaEtapaAreaTecnica_1.ATC_Id
AND a.max_TEA_InicioTarefa = TarefaEtapaAreaTecnica_1.TEA_InicioTarefa
LEFT JOIN AreaTecnica ATC ON TarefaEtapaAreaTecnica_1.ATC_Id = ATC.ATC_Id
LEFT JOIN Etapa ETS ON TarefaEtapaAreaTecnica_1.ETS_Id = ETS.ETS_Id
LEFT JOIN ParecerTipo PAT ON TarefaEtapaAreaTecnica_1.PAT_Id = PAT.PAT_Id
LEFT OUTER JOIN dbo.Servico ON a.SRV_Id = dbo.Servico.SRV_Id
INNER JOIN dbo.Intervencao ON dbo.Servico.INT_Id = dbo.Intervencao.INT_Id
LEFT JOIN dbo.Assunto ON dbo.Servico.SNT_Id = dbo.Assunto.SNT_Id
) t
结果如下:
效果很好,问题是我被问到如果此查询中不存在一行,则它必须包含来自另一个 table (ServicoAreaTecnica) 的值,所以我得到了此查询other table 基于第一个查询的关键信息。所以如果我 UNION ALL 我得到这个:
Query1 +
UNION ALL
SELECT INN.INT_Processo,
PES.PFJ_Descri,
NULL, --ETS.ETS_Sigla,
ART.ATC_Sigla,
NULL ,--PAT.PAT_Sigla,
ASS.SNT_Peso,
NULL, --PESOAREA
NULL, --DATA_INICIO_TERMINO
NULL --seqnum
FROM dbo.ServicoAreaTecnica AS SAT
INNER JOIN dbo.AreaTecnica AS ART ON ART.ATC_Id = SAT.ATC_Id
INNER JOIN dbo.Servico AS SER ON SER.SRV_Id = SAT.SRV_Id
INNER JOIN dbo.Assunto AS ASS ON ASS.SNT_Id = SER.SNT_Id
INNER JOIN dbo.Intervencao AS INN ON INN.INT_Id = SER.INT_Id
INNER JOIN dbo.Pessoa AS PES ON PES.PFJ_Id = SAT.PFJ_Id_Analista
结果如下:
所以我想做的是删除第 1 行,因为第 2 行存在于第一个查询中,我想这次我得到了更好的解释。结果应该只有第 1 行,只有当查询 1 没有检索到特定 INN.INT_Processo.
的行时,才会出现第 2 行
谢谢!
你的代码很难阅读,因为所有东西的名字都很长(老实说,它们使用的是我不会说的语言,这也让阅读变得更加困难)。
但是如何:用 LEFT JOIN
替换您的 INNER JOIN
,添加更多 LEFT JOIN
以绘制备选表格,并为每个表格引入 ISNULL
子句您想要结果中的变量?
如果您执行类似 ... Query1 Right Join Query2 On ...
的操作,则应该只获取查询 2 中未出现在查询 1 中的行。
好的,有两种方法可以减少您的记录集。鉴于您已经编写了生成带有额外行的 table 的代码,最简单的方法可能是仅添加代码来减少它:
Select * from
(Select *
, Row_Number() over
(partition by IntProcesso, Analista order by ISNULL(seqnum, 0) desc) as RN
from MyResults) a
where RN = 1
这会将 row_number
1 分配给来自第一个查询的任何行,或分配给第二个查询中在第一个查询中没有匹配项的任何行,然后过滤掉额外的行。
您也可以按照其他人的建议,将外部联接与 isnull
或 coalesce
结合使用。像这样:
Select ISNULL(a.IntProcesso, b.IntProcesso) as IntProcesso
, ISNULL(a.Analista, b.Analista) as Analista
, ISNULL(a.ETSsigla, b.ETSsigla) as ETSsigla
[repeat for the rest of your columns]
from Table1 a
full outer join Table2 b
on a.IntProcesso = b.IntProcesso and a.Analista = b.Analista
我有一个复杂的查询来检索一些结果:
EDITED QUERY(添加了 UNION ALL):
SELECT t.*
FROM (
SELECT
dbo.Intervencao.INT_Processo, analista,
ETS.ETS_Sigla, ATC.ATC_Sigla, PAT.PAT_Sigla, dbo.Assunto.SNT_Peso,
CASE
WHEN ETS.ETS_Sigla = 'PE' AND (PAT.PAT_Sigla = 'LIB' OR PAT.PAT_Sigla = 'LBR') THEN (0.3*SNT_Peso)
WHEN ETS.ETS_Sigla = 'CD' THEN (0.3*SNT_Peso)*0.3
ELSE SNT_Peso
END AS PESOAREA,
CASE
WHEN a.max_TEA_FimTarefa IS NULL THEN a.max_TEA_InicioTarefa
ELSE a.max_TEA_FimTarefa
END AS DATA_INICIO_TERMINO,
ROW_NUMBER() OVER (PARTITION BY ATC.ATC_Sigla, a.SRV_Id ORDER BY TEA_FimTarefa DESC) AS seqnum
FROM dbo.Tarefa AS t
INNER JOIN (
SELECT
MAX(dbo.TarefaEtapaAreaTecnica.TEA_InicioTarefa) AS max_TEA_InicioTarefa,
MAX (dbo.TarefaEtapaAreaTecnica.TEA_FimTarefa) AS max_TEA_FimTarefa,
dbo.Pessoa.PFJ_Descri AS analista, dbo.AreaTecnica.ATC_Id, dbo.Tarefa.SRV_Id
FROM dbo.TarefaEtapaAreaTecnica
LEFT JOIN dbo.Tarefa ON dbo.TarefaEtapaAreaTecnica.TRF_Id = dbo.Tarefa.TRF_Id
LEFT JOIN dbo.AreaTecnica ON dbo.TarefaEtapaAreaTecnica.ATC_Id = dbo.AreaTecnica.ATC_Id
LEFT JOIN dbo.ServicoAreaTecnica ON dbo.TarefaEtapaAreaTecnica.ATC_Id = dbo.ServicoAreaTecnica.ATC_Id
AND dbo.Tarefa.SRV_Id = dbo.ServicoAreaTecnica.SRV_Id
INNER JOIN dbo.Pessoa ON dbo.Pessoa.PFJ_Id = dbo.ServicoAreaTecnica.PFJ_Id_Analista
GROUP BY dbo.AreaTecnica.ATC_Id, dbo.Tarefa.SRV_Id, dbo.Pessoa.PFJ_Descri
) AS a ON t.SRV_Id = a.SRV_Id
INNER JOIN dbo.TarefaEtapaAreaTecnica AS TarefaEtapaAreaTecnica_1 ON
t.TRF_Id = TarefaEtapaAreaTecnica_1.TRF_Id
AND a.ATC_Id = TarefaEtapaAreaTecnica_1.ATC_Id
AND a.max_TEA_InicioTarefa = TarefaEtapaAreaTecnica_1.TEA_InicioTarefa
LEFT JOIN AreaTecnica ATC ON TarefaEtapaAreaTecnica_1.ATC_Id = ATC.ATC_Id
LEFT JOIN Etapa ETS ON TarefaEtapaAreaTecnica_1.ETS_Id = ETS.ETS_Id
LEFT JOIN ParecerTipo PAT ON TarefaEtapaAreaTecnica_1.PAT_Id = PAT.PAT_Id
LEFT OUTER JOIN dbo.Servico ON a.SRV_Id = dbo.Servico.SRV_Id
INNER JOIN dbo.Intervencao ON dbo.Servico.INT_Id = dbo.Intervencao.INT_Id
LEFT JOIN dbo.Assunto ON dbo.Servico.SNT_Id = dbo.Assunto.SNT_Id
) t
结果如下:
效果很好,问题是我被问到如果此查询中不存在一行,则它必须包含来自另一个 table (ServicoAreaTecnica) 的值,所以我得到了此查询other table 基于第一个查询的关键信息。所以如果我 UNION ALL 我得到这个:
Query1 +
UNION ALL
SELECT INN.INT_Processo,
PES.PFJ_Descri,
NULL, --ETS.ETS_Sigla,
ART.ATC_Sigla,
NULL ,--PAT.PAT_Sigla,
ASS.SNT_Peso,
NULL, --PESOAREA
NULL, --DATA_INICIO_TERMINO
NULL --seqnum
FROM dbo.ServicoAreaTecnica AS SAT
INNER JOIN dbo.AreaTecnica AS ART ON ART.ATC_Id = SAT.ATC_Id
INNER JOIN dbo.Servico AS SER ON SER.SRV_Id = SAT.SRV_Id
INNER JOIN dbo.Assunto AS ASS ON ASS.SNT_Id = SER.SNT_Id
INNER JOIN dbo.Intervencao AS INN ON INN.INT_Id = SER.INT_Id
INNER JOIN dbo.Pessoa AS PES ON PES.PFJ_Id = SAT.PFJ_Id_Analista
结果如下:
所以我想做的是删除第 1 行,因为第 2 行存在于第一个查询中,我想这次我得到了更好的解释。结果应该只有第 1 行,只有当查询 1 没有检索到特定 INN.INT_Processo.
的行时,才会出现第 2 行谢谢!
你的代码很难阅读,因为所有东西的名字都很长(老实说,它们使用的是我不会说的语言,这也让阅读变得更加困难)。
但是如何:用 LEFT JOIN
替换您的 INNER JOIN
,添加更多 LEFT JOIN
以绘制备选表格,并为每个表格引入 ISNULL
子句您想要结果中的变量?
如果您执行类似 ... Query1 Right Join Query2 On ...
的操作,则应该只获取查询 2 中未出现在查询 1 中的行。
好的,有两种方法可以减少您的记录集。鉴于您已经编写了生成带有额外行的 table 的代码,最简单的方法可能是仅添加代码来减少它:
Select * from
(Select *
, Row_Number() over
(partition by IntProcesso, Analista order by ISNULL(seqnum, 0) desc) as RN
from MyResults) a
where RN = 1
这会将 row_number
1 分配给来自第一个查询的任何行,或分配给第二个查询中在第一个查询中没有匹配项的任何行,然后过滤掉额外的行。
您也可以按照其他人的建议,将外部联接与 isnull
或 coalesce
结合使用。像这样:
Select ISNULL(a.IntProcesso, b.IntProcesso) as IntProcesso
, ISNULL(a.Analista, b.Analista) as Analista
, ISNULL(a.ETSsigla, b.ETSsigla) as ETSsigla
[repeat for the rest of your columns]
from Table1 a
full outer join Table2 b
on a.IntProcesso = b.IntProcesso and a.Analista = b.Analista