JS reduce: object 累加器标题

JS reduce: object accumulator titles

我目前正在试验 reduce 函数,想知道是否可以将累加器的键名定制为特定值?

例如,下面的代码 returns {16 years of experience: ... } 但我希望 return 结果分类如下:

Results wanted in this format:

{ Over 10 years:
  16: {
    {name: "Company One", category: "Finance", start: 1981, end: 2003},
    {name: "Company Two", category: "Retail", start: 1992, end: 2008}

  },


  20: { 
  {name: "Company One", category: "Finance", start: 1981, end: 2003},
  {name: "Company Two", category: "Retail", start: 1992, end: 2008}
  }

  ...
} etc...


const companies = [
    {name: "Company One", category: "Finance", start: 1981, end: 2003},
    {name: "Company Two", category: "Retail", start: 1992, end: 2008},
    {name: "Company Three", category: "Auto", start: 1999, end: 2007},
    {name: "Company Four", category: "Retail", start: 1989, end: 2010},
    {name: "Company Five", category: "Technology", start: 2009, end: 2014},
    {name: "Company Six", category: "Finance", start: 1987, end: 2010},
    {name: "Company Seven", category: "Auto", start: 1986, end: 1996},
    {name: "Company Eight", category: "Technology", start: 2011, end: 2016},
    {name: "Company Nine", category: "Retail", start: 1981, end: 1989}
  ];
  

const industryExeperience = (obj, keyStart, keyEnd)=>{
  return obj.reduce((exp, curObj)=>{
    let differences = curObj[keyEnd] - curObj[keyStart];
    console.log(differences)
    if(differences > 10){
      exp[differences + ' years of experience'] = curObj

    }
    return exp
  },{})
}

console.log(industryExeperience(companies, 'start', 'end'))



要按年份分组,请使用差异作为键,使用数组作为值。 将每个项目推入或连接到现有数组或根据需要添加新项目

const companies = [
    {name: "Company One", category: "Finance", start: 1981, end: 2003},
    {name: "Company Two", category: "Retail", start: 1992, end: 2008},
    {name: "Company Three", category: "Auto", start: 1999, end: 2007},
    {name: "Company Four", category: "Retail", start: 1989, end: 2010},
    {name: "Company Five", category: "Technology", start: 2009, end: 2014},
    {name: "Company Six", category: "Finance", start: 1987, end: 2010},
    {name: "Company Seven", category: "Auto", start: 1986, end: 1996},
    {name: "Company Eight", category: "Technology", start: 2011, end: 2016},
    {name: "Company Nine", category: "Retail", start: 1981, end: 1989}
  ];
  
const grouped = companies.reduce((a,c)=>{
    const diff = c.end - c.start;
    a[diff] = (a[diff] || []).concat(c)
    return a;
},{})

console.log(grouped)