如何推动元素反应挂钩状态数组

How to push elements to react hooks state array

我正在使用 react-bootstrap-table2 制作 HTML table,我正在使用 table 中的复选框来删除项目。

SO 根据 This link,提到了如何获取 selected 行然后执行下一部分,这里我正在做的是当我单击任何复选框行时得到 selected,如果我再次 select 我添加到数组中的任何行进入我的状态,如下所示

onSelect: (row, isSelect, rowIndex, e) => {
        if (isSelect === true) {
            setrowData((rowData) => [...rowData, row]);
        } else {
        //  here i need to do something
        }
    },

我的问题是,当我取消select 值未从我的数组中删除的行时,在删除时,我拥有我 select 编辑过一次的所有数据.

我为此所做的事情如下所示

setrowSelect((rowSelect) => [...rowSelect, isSelect]); // this one is inside onSelect callback given by the react-bootstrap-table2 library

           {rowSelect && (
                    <button className="btn Secondary_Button_with_Icon">
                        <i className="ri-upload-cloud-line ri-lg"></i>Register
                    </button>
                )}

My full working code

在 else 块中使用过滤方法从数组中删除未选择的元素

 onSelect: (row, isSelect, rowIndex, e) => {
      if (isSelect === true) {
        setrowData((rowData) => [...rowData, row]);
      } else {
        setrowData((rowData) => rowData.filter((x,i)=>i!==rowIndex))
      }
      setrowSelect((rowSelect) => [...rowSelect, isSelect]);
    },

尝试像这样更改 onSelect 函数

  onSelect: (row, isSelect, rowIndex, e) => {
  if (isSelect === true) {
    setrowData((rowData) => [...rowData, row]);
    rowSelect.push(true);
    setrowSelect(rowSelect);
  } else {
    setrowData((rowData) => rowData.filter((x, i) => i !== rowIndex));     
      rowSelect.pop();
      setrowSelect(rowSelect);
  }
}

这是一种实现您想要的方法:

1.Keep 你的数据在一个对象中,并添加一个 idisSelect 字段

const data = [
  {
    id: "id-1",
    fname: "john",
    lname: "smith",
    isSelect: false
  },
  {
    id: "id-2",
    fname: "steve",
    lname: "warn",
    isSelect: false
  },
  {
    id: "id-3",
    fname: "michel",
    lname: "clark",
    isSelect: false
  }
];

2.pass 这个数据到 useState :

const [rowData, setrowData] = useState(data);

3.onSelect :只需按 id 查找行并设置 isSelect 字段

onSelect: (row, isSelect, rowIndex, e) => {
  setrowData((rows) => {
    return rows.map((r) => {
      if (r.id !== row.id) {
        return r;
      }

      return { ...r, isSelect };
    });
  });
},

4.onSelectAll 在所有行上设置 isSelect

onSelectAll: (isSelect, rows, e) => {
  setrowData((rows) => {
    return rows.map((row) => {
      return { ...row, isSelect };
    });
  });
}

5.for Delete_device 只过滤没有选中的数据:

  const Delete_device = () => {
    setrowData((rows) => {
      return rows.filter((row) => !row.isSelect);
    });
  };

6.for 删除按钮,获取选定的行并对其进行计数,如果计数 > 0 则显示按钮:

const selectedRows = rowData.filter((row) => row.isSelect);

  return (
    <div className="App">
      {selectedRows.length > 0 && (
        <button className="btn btn-primary" onClick={Delete_device}>
          <i className="ri-upload-cloud-line ri-lg"></i>Delete
        </button>
      )}

7.Pass状态数据到BootstrapTable

  <BootstrapTable
    bootstrap4
    keyField="fname"
    data={rowData}
    columns={tableData[0].columnsData}
    selectRow={selectRow}
  />

Complete example

我更新了您的状态以使用您的数据并从您的 select 逻辑中删除了 select 数组。我也对其进行了一些优化。它与您的 codesandbox 示例相比有细微的变化。另外,我建议你使用ids。

import React, { useState, useMemo } from "react";
import "./styles.css";
import "bootstrap/dist/css/bootstrap.min.css";
import BootstrapTable from "react-bootstrap-table-next";
import "react-bootstrap-table-next/dist/react-bootstrap-table2.min.css";

let tableData = [
  {
    rowsData: [
      {
        fname: "john",
        lname: "smith"
      },
      {
        fname: "steve",
        lname: "warn"
      },
      {
        fname: "michel",
        lname: "clark"
      }
    ],
    columnsData: [
      {
        dataField: "fname",
        text: "First name",
        sort: true
      },
      {
        dataField: "lname",
        text: "last Name",
        sort: true
      }
    ]
  }
];

export default function App() {
  const [rowData, setrowData] = useState(tableData[0].rowsData);
  const [rowSelect, setrowSelect] = useState([]);

  const selectRow = useMemo(
    () => ({
      mode: "checkbox",
      clickToSelect: false,
      classes: "selection-row",
      onSelect: (row, isSelect, rowIndex, e) => {
        setrowSelect((rowData) =>
          isSelect
            ? [...rowData, row]
            : rowData.filter(
                ({ fname, lname }) => row.fname !== fname && row.lname !== lname
              )
        );
        // if (isSelect === true) {
        //   setrowSelect((rowData) => [...rowData, row]);
        // } else {
        //   console.log("onSelect", rowIndex, row, isSelect);
        //   setrowSelect((rowData) =>
        //     rowData.filter(
        //       ({ fname, lname }) => row.fname !== fname && row.lname !== lname
        //     )
        //   );
        // }
      },

      onSelectAll: (isSelect, rows, e) => {
        if (isSelect === true) {
          setrowSelect(rows);
        } else setrowSelect([]);
      }
    }),
    []
  );
  const Delete_device = () => {
    console.log("Delete device", rowData, rowSelect);
    if (rowSelect.length < 1) return;
    setrowData((data) =>
      data.filter(
        ({ fname, lname }) =>
          rowSelect.find((s) => s.fname === fname && s.lname === lname) == null
      )
    );
    setrowSelect([]);
  };
  console.log("App", rowData, rowSelect);
  return (
    <div className="App">
      {rowData.length > 0 && (
        <button className="btn btn-primary" onClick={Delete_device}>
          <i className="ri-upload-cloud-line ri-lg"></i>Delete
        </button>
      )}
      <BootstrapTable
        bootstrap4
        keyField="fname"
        data={rowData}
        columns={tableData[0].columnsData}
        selectRow={selectRow}
      />
    </div>
  );
}

https://codesandbox.io/s/react-bootstrap-table-x-wus5r?file=/src/App.js

请注意,您不需要维护另一个状态来控制 Delete 按钮的可见性。

You can perfectly hide/show Delete based on rowData state.

您为处理选定行而编写的代码也能很好地工作。只需摆脱 rowSelect 状态及其处理程序。

并根据 rowData 的内容更新 Delete 按钮的渲染:

{
    rowData.length ? (
        <button className="btn btn-primary" onClick={Delete_device}>
          <i className="ri-upload-cloud-line ri-lg"></i>Delete
        </button>
      )
    : null
}

这是你的forked sandbox