Laravel : 如何使用查询生成器获取列中的对象

Laravel : How to get object in column with query builder

我想展示我在下面描述的那种数据,但我不知道关键字。

现在,这是我的数据:

这就是我想要的结果:

这是我的控制器:

$data = DB::table('tr_doctor_schedules as sch')
    ->select('sch.id as schedule_id','doctor_name','hospital_name','estimated_practice_time','day','from_time','until_time')
    ->join('mst_hospitals as hos', 'hos.id', '=', 'sch.hospital_id')
    ->join('mst_doctors as doc', 'doc.id', '=', 'sch.doctor_id')
    ->join('tr_doctor_schedule_details as dtl', 'dtl.doctor_schedule_id', '=', 'sch.id')
    ->where('sch.hospital_id', $hosId)
    ->where('sch.doctor_id', $docId)
    ->first();

if ($data) {
    return response()->json([
        'success' => true,
        'message' =>'success',
        'data'    => $data
    ], 200);
} else {
    return response()->json([
        'success' => false,
        'message' => 'Data not found.',
    ], 400);
}

谢谢

试试这个

   $data = DB::table('tr_doctor_schedules as sch')
        ->selectRaw('sch.id as schedule_id,doctor_name,hospital_name,estimated_practice_time,GROUP_CONCAT(day) as day,from_time,until_time')
        ->join('mst_hospitals as hos', 'hos.id', '=', 'sch.hospital_id')
        ->join('mst_doctors as doc', 'doc.id', '=', 'sch.doctor_id')
        ->join('tr_doctor_schedule_details as dtl', 'dtl.doctor_schedule_id', '=', 'sch.id')
        ->where('sch.hospital_id', $hosId)
        ->where('sch.doctor_id', $docId)
        ->groupBy('sch.id')
        ->first();