在具有差异列的 postgres 中创建视图

Question

我有一个独特的 table 包含同一列中的人员和组织的混合数据，只有一个字段只有 1 个字母设置数据引用。

例子

id|type | surname of person/organization | name of person/address of organization | person sex/organization fiscal code
 1|   P | GATES                          | BILL                                   | M
 2|   O | GOOGLE                         | PALO ALTO                              | 04340349204920
 3|   P | DOE                            | JENNIFER                               | F
...etc....

我想在 Postgres 中创建一个按引用类型（字母）组织和分隔信息的视图，如下所示

id|type|surname|name      |sex|organization|address    |fiscal code
 1| P  | GATES | BILL     | M |            |           |         
 2| O  |       |          |   | GOOGLE     | PALO ALTO | 04340349204920
 3| P  | DOE   | JENNIFER | F |            |           |

我认为这应该很简单（对我来说），但我卡住了。

Answer 1

您可以使用 case 表达式：

create view myview (surname, name, sex, orga, address, fiscal_code) as
select
    id,
    type,
    case when type = 'P' then surname_or_orga    end as surname,
    case when type = 'P' then name_or_address    end as name,
    case when type = 'P' then sex_or_fiscal_code end as sex,
    case when type = 'O' then surname_or_orga    end as orga,
    case when type = 'O' then name_or_address    end as address,
    case when type = 'O' then sex_or_fiscal_code end as fiscal_code
from mytable

在具有差异列的 postgres 中创建视图

create a view in postgres with differential columns

sql

postgresql

case

sql-view