在 python3 中检测到输入之前如何做某事？

Question

我想执行一段代码直到用户输入（检测到随机按键），我如何在 Python [=18 中执行此操作=]?

这是伪代码：

while input == False:
    print(x)

Answer 1

你可以这样做：

try:
    while True:
        print("Running")
except KeyboardInterrupt:
    print("User pressed CTRL+c. Program terminated.")

用户只需按 Control+c。

Python 提供 built-in 异常 KeyboardInterrupt 来处理这个问题。

用 pynput

随机 key-press

import threading
from pynput.keyboard import Key, Listener

class MyClass():
    def __init__(self) -> None:
        self.user_press = False

    def RandomPress(self, key):
        self.user_press = True

    def MainProgram(self):
        while self.user_press == False:
            print("Running")
        print("Key pressed, program stop.")

    def Run(self):
        t1 = threading.Thread(target=self.MainProgram)
        t1.start()

        # Collect events until released
        with Listener(on_press=self.RandomPress) as listener:
            listener.join()

MyClass().Run()

Answer 2

如果您想与用户进行互动，您可以按照以下方式进行：

flag = input("please enter yes or no?")
if flag == "no":
    print(x)

在 python3 中检测到输入之前如何做某事？

How to do something till an input is detected in python3?

python

user-input

input

python-3.x