使用 python 访问 yaml 中的元素
Access elements inside yaml using python
我正在使用 yaml 和 pyyaml 配置我的应用程序。
是否可以这样配置-
config.yml -
root:
repo_root: /home/raghhuveer/code/data_science/papers/cv/AlexNet_lght
data_root: $root.repo_root/data
service:
root: $root.data_root/csv/xyz.csv
yaml加载函数-
def load_config(config_path):
config_path = os.path.abspath(config_path)
if not os.path.isfile(config_path):
raise FileNotFoundError("{} does not exist".format(config_path))
else:
with open(config_path) as f:
config = yaml.load(f, Loader=yaml.SafeLoader)
# logging.info(config)
logging.info("Config used for run - \n{}".format(yaml.dump(config, sort_keys=False)))
return DotDict(config)
当前输出-
root:
repo_root: /home/raghhuveer/code/data_science/papers/cv/AlexNet_lght
data_root: ${root.repo_root}/data
service:
root: ${root.data_root}/csv/xyz.csv
期望输出 -
root:
repo_root: /home/raghhuveer/code/data_science/papers/cv/AlexNet_lght
data_root: /home/raghhuveer/code/data_science/papers/cv/AlexNet_lght/data
service:
root: /home/raghhuveer/code/data_science/papers/cv/AlexNet_lght/data/csv/xyz.csv
python甚至可以做到这一点吗?如果是这样,任何帮助都会非常好。
提前致谢。
一般方法:
- 按原样读取文件
- 搜索包含
$
的字符串:
- 确定“变量”的“路径”
- 用实际值替换“变量”
一个例子,使用递归调用字典和替换字符串:
import re, pprint, yaml
def convert(input,top=None):
"""Replaces $key1.key2 with actual values. Modifies input in-place"""
if top is None:
top = input # top should be the original input
if isinstance(input,dict):
ret = {k:convert(v,top) for k,v in input.items()} # recursively convert items
if input != ret: # in case order matters, do it one or several times more until no change happens
ret = convert(ret)
input.update(ret) # update original input
return input # return updated input (for the case of recursion)
if isinstance(input,str):
vars = re.findall(r"$[\w_\.]+",input) # find $key_1.key_2.keyN sequences
for var in vars:
keys = var[1:].split(".") # remove dollar and split by dots to make "key chain"
val = top # starting from top ...
for k in keys: # ... for each key in the key chain ...
val = val[k] # ... go one level down
input = input.replace(var,val) # replace $key sequence eith actual value
return input # return modified input
# TODO int, float, list, ...
with open("in.yml") as f: config = yaml.load(f) # load as is
convert(config) # convert it (in-place)
pprint.pprint(config)
输出:
{'root': {'data_root': '/home/raghhuveer/code/data_science/papers/cv/AlexNet_lght/data',
'repo_root': '/home/raghhuveer/code/data_science/papers/cv/AlexNet_lght'},
'service': {'root': '/home/raghhuveer/code/data_science/papers/cv/AlexNet_lght/data/csv/xyz.csv'}}
注意:YAML 在这里并不那么重要,它也适用于 JSON、XML 或其他格式。
注意 2:如果您只使用 YAML 并且只使用 python,this post 的一些答案可能会有用(使用锚点和引用以及特定于应用程序的本地标签)
我正在使用 yaml 和 pyyaml 配置我的应用程序。
是否可以这样配置-
config.yml -
root:
repo_root: /home/raghhuveer/code/data_science/papers/cv/AlexNet_lght
data_root: $root.repo_root/data
service:
root: $root.data_root/csv/xyz.csv
yaml加载函数-
def load_config(config_path):
config_path = os.path.abspath(config_path)
if not os.path.isfile(config_path):
raise FileNotFoundError("{} does not exist".format(config_path))
else:
with open(config_path) as f:
config = yaml.load(f, Loader=yaml.SafeLoader)
# logging.info(config)
logging.info("Config used for run - \n{}".format(yaml.dump(config, sort_keys=False)))
return DotDict(config)
当前输出-
root:
repo_root: /home/raghhuveer/code/data_science/papers/cv/AlexNet_lght
data_root: ${root.repo_root}/data
service:
root: ${root.data_root}/csv/xyz.csv
期望输出 -
root:
repo_root: /home/raghhuveer/code/data_science/papers/cv/AlexNet_lght
data_root: /home/raghhuveer/code/data_science/papers/cv/AlexNet_lght/data
service:
root: /home/raghhuveer/code/data_science/papers/cv/AlexNet_lght/data/csv/xyz.csv
python甚至可以做到这一点吗?如果是这样,任何帮助都会非常好。
提前致谢。
一般方法:
- 按原样读取文件
- 搜索包含
$
的字符串:- 确定“变量”的“路径”
- 用实际值替换“变量”
一个例子,使用递归调用字典和替换字符串:
import re, pprint, yaml
def convert(input,top=None):
"""Replaces $key1.key2 with actual values. Modifies input in-place"""
if top is None:
top = input # top should be the original input
if isinstance(input,dict):
ret = {k:convert(v,top) for k,v in input.items()} # recursively convert items
if input != ret: # in case order matters, do it one or several times more until no change happens
ret = convert(ret)
input.update(ret) # update original input
return input # return updated input (for the case of recursion)
if isinstance(input,str):
vars = re.findall(r"$[\w_\.]+",input) # find $key_1.key_2.keyN sequences
for var in vars:
keys = var[1:].split(".") # remove dollar and split by dots to make "key chain"
val = top # starting from top ...
for k in keys: # ... for each key in the key chain ...
val = val[k] # ... go one level down
input = input.replace(var,val) # replace $key sequence eith actual value
return input # return modified input
# TODO int, float, list, ...
with open("in.yml") as f: config = yaml.load(f) # load as is
convert(config) # convert it (in-place)
pprint.pprint(config)
输出:
{'root': {'data_root': '/home/raghhuveer/code/data_science/papers/cv/AlexNet_lght/data',
'repo_root': '/home/raghhuveer/code/data_science/papers/cv/AlexNet_lght'},
'service': {'root': '/home/raghhuveer/code/data_science/papers/cv/AlexNet_lght/data/csv/xyz.csv'}}
注意:YAML 在这里并不那么重要,它也适用于 JSON、XML 或其他格式。
注意 2:如果您只使用 YAML 并且只使用 python,this post 的一些答案可能会有用(使用锚点和引用以及特定于应用程序的本地标签)