如何从特定索引的字符串中删除子字符串到 swift 中的某个长度

Question

我有一个字符串，比方说，

var myString = "thisIsMyAutoGeneratedRandomString"

比方说，我想从索引 8 到 26 中删除一些字符。我需要像

这样的输出

print(myString)   //thisIsMyString  --> This is what i want.

我试过 base1.remove(at: base1.index(i: String.Index, offsetBy: String.IndexDistance)) 作为 base1.remove(at: base1.index(i: 8, offsetBy: 26))

但我收到类似警告 Cannot convert value of type 'Int' to expected argument type 'String.Index'

我尝试了很多东西，但没有运气。

Answer 1

你可以用 replacingOccurrences

var myString = "thisIsMyAutoGeneratedRandomString"
let parsed = myString.replacingOccurrences(of: "AutoGeneratedRandom", with: "")
print(myString) //"thisIsMyString"

Answer 2

var myString = "thisIsMyAutoGeneratedRandomString"

let ix = myString.startIndex // the index of 1st character
let ix2 = myString.index(ix, offsetBy: 8) // the index of 8th character
let ix3 = myString.index(ix, offsetBy: 26) // the index of 26th character

myString.removeSubrange(ix2...ix3)

print(myString) //thisIsMyString

Answer 3

使用 prefix 获得简单的解决方案

let firstPart = myString.prefix(8)

Answer 4

Swift解决方案前缀或let lastPart = date.suffix(16)

如何从特定索引的字符串中删除子字符串到 swift 中的某个长度

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