取 'n' space 分隔的整数在 Python 中，存储在矩阵中并打印矩阵

Question

我想取 n space 分隔的整数并存储在矩阵中，然后打印矩阵。我正在使用 Python 3.7.

我的代码是：


size = int(input("\nEnter number of rows or colums: ")) #square matrix

#Define the matrix
matrix = []
print("\nEnter the entries:")

#for user input
for row in range(size):     
    temp = []
    for column in range(size):      
        temp.append(int(input()))
    matrix.append(temp)


#To print the matrix
print("\nThe matrix is :")
for i in range(size):
    for j in range(size):
        print(matrix[i][j], end="\t")
    print()

我只能接受这样的输入

Enter number of rows or colums: 2

Enter the entries:
1
2
3
4

The matrix is :
1       2
3       4

但我想接受这样的输入

Enter number of rows or colums: 2

Enter the entries:
1 2
3 4

The matrix is :
1       2
3       4

如果我尝试使用 space 分隔的整数，然后按 Enter 换行，我会得到下面的错误消息

Enter number of rows or colums: 2

Enter the entries:
1 2
Traceback (most recent call last):
  File "e:/Python/matrix.py", line 12, in <module>
    temp.append(int(input()))
ValueError: invalid literal for int() with base 10: '1 2'

谁能帮帮我？提前致谢。

Answer 1

这是更新后的代码：

size = int(input("\nEnter number of rows or colums: ")) #square matrix

#Define the matrix
matrix = []
print("\nEnter the entries:")

#for user input
for row in range(size):
    # Read row, space separated value
    matrix.append(
        [int(n) for n in input().split(' ')]
    )

#To print the matrix
print("\nThe matrix is :")
for i in range(size):
    for j in range(size):
        print(matrix[i][j], end="\t")
    print()

取 'n' space 分隔的整数在 Python 中，存储在矩阵中并打印矩阵

Taking 'n' space separated integers in Python, storing in matrix and print the matrix

python

user-input

matrix

python-3.x