如何找到用户输入数组中的最小元素？为什么最小的元素显示为零？

Question

代码显示总和、平均值和最大元素。它不显示最小的元素，因为输出始终为零。如何显示数组中最小的元素？

import java.util.Scanner;
public class Average {

    public static void main (String[] args) {
        
        Scanner input = new Scanner(System.in);
        
        System.out.println("Enter the number of elements:");
        int length = input.nextInt();
        
        int[] num = new int[length];
        System.out.println("Enter the "+ length +  " array elements:");
        int sum = 0;
         int large,small;
         large =small = num[0]; 
         
         for (int i=0; i<length;i++) {
            num[i] = input.nextInt();
            sum = sum+ num[i];
              }
         
        for (int i=0; i<length; ++i) {
            if (num[i]<small) {
                 small = num[i];
            }
              
             if(num[i]> large) {
                 large = num[i];
            }
             }
        
        double avg = sum/length;
        System.out.println("The sum is "+ sum);
        System.out.println("The average is "+ avg);
        System.out.println("The smallest element is "+ small);
        System.out.println("The largest element is "+ large);
        }
}

Answer 1

是的，这是因为默认情况下您的字段 small 等于 0。

现在让我们逐步查看您的 if 语句

        if (num[i]<small) {
             small = num[i];
        }

数字示例：22,11,6,

So first step is num[0] < 0, why 0 as mention before small = 0 by default
Step two num[1] < 0, small stills stay 0
Step Three num[2] < 0, small stills stay 0.

你错过了什么，你需要在 for 循环的第一次迭代时将值赋给 small，例如：

       for (int i=0; i<length; ++i) {
            if(i == 0){
                small = num[i];
            }
            if (num[i]<small) {
                small = num[i];
            }

            if(num[i]> large) {
                large = num[i];
            }
        }

现在你的程序应该可以运行了:)

Answer 2

import java.util.Scanner;

class Average {
    public static void main(String[] args) {

        Scanner input = new Scanner(System.in);

        System.out.println("Enter the number of elements:");
        int length = input.nextInt();

        int[] num = new int[length];
        System.out.println("Enter the " + length + " array elements:");
        int sum = 0;
        int large, small;

        for (int i = 0; i < length; i++) {
            num[i] = input.nextInt();
            sum = sum + num[i];
        }

        large = small = num[0]; // small should be assigned after num is input
        
        for (int i = 0; i < length; ++i) {
            if (num[i] < small) {
                small = num[i];
            }

            if (num[i] > large) {
                large = num[i];
            }
        }

        double avg = sum / length;
        System.out.println("The sum is " + sum);
        System.out.println("The average is " + avg);
        System.out.println("The smallest element is " + small);
        System.out.println("The largest element is " + large);

    }
}

Answer 3

如果使用java8以上，可以使用Arrays的stream方法。它简化了数组的工作。 for more info

首先将数组导入为import java.util.Arrays;

System.out.println("The sum is " + Arrays.stream(num).sum());
System.out.println("The average is " + Arrays.stream(num).average());
System.out.println("The smallest element is " + Arrays.stream(num).min());
System.out.println("The largest element is " + Arrays.stream(num).max());

如何找到用户输入数组中的最小元素？为什么最小的元素显示为零？

How to find the smallest element in an user inputted array? Why the smallest element is displayed zero?

java

arrays

element