Azure DevOps 为 Winforms 应用程序构建管道

Azure DevOps Build PIpeline for Winforms Application

我有一个 WinForms 应用程序。我已经为此创建了一个构建管道,但无法在 Artifacts 中获取任何内容。

实际上我需要 Zipped 文件夹中的项目构建。任何相同的参考将不胜感激。

以下是管道的 Yaml 文件。

trigger:
- master

pool:
  vmImage: 'windows-latest'

variables:
  solution: '**/*.sln'
  buildPlatform: 'Any CPU'
  buildConfiguration: 'Release'
  ScmBuildProject: 'DemoAppForAzurePipeLine'

steps:
- task: NuGetToolInstaller@1

- task: NuGetCommand@2
  inputs:
    restoreSolution: '$(solution)'

- task: VSBuild@1
  inputs:
    solution: '$(solution)'
    platform: '$(buildPlatform)'
    configuration: '$(buildConfiguration)'

- task: VSTest@2
  inputs:
    platform: '$(buildPlatform)'
    configuration: '$(buildConfiguration)'

- task: PublishBuildArtifacts@1
  displayName: 'Publish Artifact: $(ScmBuildName)'
  inputs:
    PathtoPublish: '$(build.artifactstagingdirectory)'
    ArtifactName: '$(ScmBuildName)'
  condition: succeededOrFailed()

假设您的构建输出在这里 $(Build.SourcesDirectory)/YourProject/bin/release/' 您可以使用 archive task

- task: ArchiveFiles@2
  inputs:
    rootFolderOrFile: '$(Build.SourcesDirectory)/YourProject/bin/release/'
    #includeRootFolder: true 
    #archiveType: 'zip' # Options: zip, 7z, tar, wim
    #tarCompression: 'gz' # Optional. Options: gz, bz2, xz, none
    #archiveFile: '$(Build.ArtifactStagingDirectory)/$(Build.BuildId).zip' 
    #replaceExistingArchive: true 
    #verbose: # Optional
    #quiet: # Optional

然后将其放入 archiveFile $(Build.ArtifactStagingDirectory)/$(Build.BuildId).zip'

将此步骤放在PublishBuildArtifacts之前应该没问题。请仔细检查二进制文件的输出路径(我的意思是 $(Build.SourcesDirectory)/YourProject/bin/release/