vim 替换 : # 对于单个 $ 并且如果 $$ 则无事可做
vim substitution : # for a single $ and nothing to do if $$
我想做以下替换：将位于 2 $ 之间的单词 $ 替换为符号 #，如果这些单词位于 2 $$ 之间，则不执行任何操作。
例如，在本文中：
Currently, we are able to make cross correlations (understand "combine" to have better constraints on cosmological parameters) between weak lensing (WL) and photometric Galaxy clustering (GCph). When I say combine, as in the case where I have 2 sets of different measures ($\tau_1, \sigma_1$) and ($\tau_2, \sigma_2$), well, if I consider the Gaussian errors, it is shown quite easily (by Maximum Likelihood Estimation) that the estimator $\sigma_{\hat {\tau}}$ the most representative matches the relation:
$$\dfrac{1}{\sigma_{\hat{\tau}}^{2}}=\dfrac{1}{\sigma_1^2}+\dfrac{1}{\sigma_2^2}$$
替换会得到：
Currently, we are able to make cross correlations (understand "combine" to have better constraints on cosmological parameters) between weak lensing (WL) and photometric Galaxy clustering (GCph). When I say combine, as in the case where I have 2 sets of different measures (#\tau_1, \sigma_1#) and (#\tau_2, \sigma_2#), well, if I consider the Gaussian errors, it is shown quite easily (by Maximum Likelihood Estimation) that the estimator #\sigma_{\hat {\tau}}# the most representative matches the relation:
$$\dfrac{1}{\sigma_{\hat{\tau}}^{2}}=\dfrac{1}{\sigma_1^2}+\dfrac{1}{\sigma_2^2}$$
我尝试在 vim 下使用以下命令执行此操作：
%s/$[^$]\(.*\)$[^$]/##/g
或
%s/$[^$]\(.\{-}\)$[^$]/##/g
但这不起作用。我看不到我的错误。
您可以在 vim 中使用负前瞻和负后瞻来使用此正则表达式替换：
搜索：
:%s/\v$@<!$([^$]+)$$@!/##/g
替换：
##
解释：
%s/：全局替换\v: 开始非常神奇的模式而不是 BRE$@<!：否定回顾断言我们在之前的位置$
$：匹配文字$([^$]+)：匹配任何非 $ 的字符的 1+ 并在组 #1$：匹配文字$$@!：否定前瞻断言我们没有$提前##：用 #
我想做以下替换：将位于 2 $ 之间的单词 $ 替换为符号 #，如果这些单词位于 2 $$ 之间，则不执行任何操作。
例如，在本文中：
Currently, we are able to make cross correlations (understand "combine" to have better constraints on cosmological parameters) between weak lensing (WL) and photometric Galaxy clustering (GCph). When I say combine, as in the case where I have 2 sets of different measures ($\tau_1, \sigma_1$) and ($\tau_2, \sigma_2$), well, if I consider the Gaussian errors, it is shown quite easily (by Maximum Likelihood Estimation) that the estimator $\sigma_{\hat {\tau}}$ the most representative matches the relation:
$$\dfrac{1}{\sigma_{\hat{\tau}}^{2}}=\dfrac{1}{\sigma_1^2}+\dfrac{1}{\sigma_2^2}$$
替换会得到：
Currently, we are able to make cross correlations (understand "combine" to have better constraints on cosmological parameters) between weak lensing (WL) and photometric Galaxy clustering (GCph). When I say combine, as in the case where I have 2 sets of different measures (#\tau_1, \sigma_1#) and (#\tau_2, \sigma_2#), well, if I consider the Gaussian errors, it is shown quite easily (by Maximum Likelihood Estimation) that the estimator #\sigma_{\hat {\tau}}# the most representative matches the relation:
$$\dfrac{1}{\sigma_{\hat{\tau}}^{2}}=\dfrac{1}{\sigma_1^2}+\dfrac{1}{\sigma_2^2}$$
我尝试在 vim 下使用以下命令执行此操作：
%s/$[^$]\(.*\)$[^$]/##/g
或
%s/$[^$]\(.\{-}\)$[^$]/##/g
但这不起作用。我看不到我的错误。
您可以在 vim 中使用负前瞻和负后瞻来使用此正则表达式替换：
搜索：
:%s/\v$@<!$([^$]+)$$@!/##/g
替换：
##
解释：
%s/：全局替换\v: 开始非常神奇的模式而不是 BRE$@<!：否定回顾断言我们在之前的位置 没有$：匹配文字$([^$]+)：匹配任何非$的字符的 1+ 并在组 #1 中捕获它
$：匹配文字$$@!：否定前瞻断言我们没有$提前##：用# 包围的第 1 组的 back-reference 替换
$