查询以显示不同的组合，然后显示每个不同组合的计数

Question

此 table 中存在多行的 transid 字段，其中包含配置值列表。对于所有 transid，我想按计数

检索存在于 table 组中的所有 transid、config_name 和值字段的不同组合

我的连接查询没有按预期返回结果。以下是 table 结构、使用的查询、结果和预期结果

Table

transid            config_name               value
1                   payment_fee                instant
2                   eligible_account           true
1                   Block_intl_trans           false
5                   payment_fee                provider_charge
1                   eligible_account           false  
1                         KycEligible               0
2                         KycEligible               1
5                        KycEligible                1
5                   Block_intl_trans            true
2                   Block_intl_trans            false   
2                   payment_fee                 provider_charge
5                   eligible_account            true

上面的table结构意味着下面是每个用户的配置值组合。

transid  KycEligible  payment_fee     eligible_account     Block_intl_trans
1      0            instant          false                false
2      1            provider_charge  true                 false
5      1            provider_charge  true                 false

下面是我用来将行转换为列然后按 config_name 对它们进行分组的查询（对于每个 config_name，而不是每个配置键和值组合的多行）。然后 select table 中存在的 KycEligible、configname 和值组合的所有不同组合以及每个不同组合的计数。

select
    distinct
    max(case when b.config_name = 'KycEligible' then b.config_value end) KycEligible,
    max(case when b.config_name = 'payment_fee' then b.config_value end)  payment_fee,
    max(case when b.config_name = 'eligible_account' then b.config_value end)  eligible_account,
    max(case when b.config_name = 'Block_intl_trans' then b.config_value end)  Block_intl_trans,
    count(*) AS COUNT
from tableA b
where b.config_name in ('KycEligible', 'payment_fee', 'eligible_account', 'Block_intl_trans')
group by b.config_name
having count(*) > 1

预期结果：

KycEligible  payment_fee     eligible_account     Block_intl_trans  Count
    0            instant          false                false             1
    1            provider_charge  true                 false             2

我的查询没有返回预期的结果。有人可以帮忙解决这个问题吗？

Answer 1

我想你需要这样的东西：

SELECT
  KycEligible, payment_fee, eligible_account, Block_intl_trans, COUNT(*) CNT
FROM (
  SELECT
    (SELECT MAX(t0.config_value) FROM test t0 WHERE t0.config_name = 'KycEligible' AND t0.transid = t.transid) as KycEligible,
    (SELECT MAX(t0.config_value) FROM test t0 WHERE t0.config_name = 'payment_fee' AND t0.transid = t.transid) as payment_fee,
    (SELECT MAX(t0.config_value) FROM test t0 WHERE t0.config_name = 'eligible_account' AND t0.transid = t.transid) as eligible_account,
    (SELECT MAX(t0.config_value) FROM test t0 WHERE t0.config_name = 'Block_intl_trans' AND t0.transid = t.transid) as Block_intl_trans
  FROM
    test t
  GROUP BY t.transid
) dt
GROUP BY KycEligible, payment_fee, eligible_account, Block_intl_trans
;

这将给出以下结果：

ycEligible  payment_fee         eligible_account    Block_intl_trans    CNT
0           instant○            false               false                   1
1           provider_charge     true                false                   1
1           provider_charge     true                true                    1

结果与问题中的预期不同：

2 and 5 transids have different Block_intl_trans
1 and 5 transids have different payment_fee
1 and 2 transids have different eligible_account

Answer 2

我给出了两个 fiddle 示例，因为您提供的示例数据不一致。

此 fiddle 适用于 transid=5 且 Block_intl_trans 数据为 true - 与您的 table 数据示例一致：https://www.db-fiddle.com/f/r1imsYP8dQxkLSo5SkYcVK/3
这个fiddle是for transid=5 with Block_intl_trans数据是false - 和你说明的配置组合一致：https://www.db-fiddle.com/f/r1imsYP8dQxkLSo5SkYcVK/4

我猜测唯一组合将来自所有 config_name 值。这是示例查询：

SELECT KycEligible, payment_fee, eligible_account, Block_intl_trans, COUNT(*) FROM
(SELECT transid,
       GROUP_CONCAT(CASE WHEN config_name="KycEligible" THEN config_value END) AS "KycEligible",
       GROUP_CONCAT(CASE WHEN config_name="payment_fee" THEN config_value END) AS "payment_fee",
       GROUP_CONCAT(CASE WHEN config_name="eligible_account" THEN config_value END) AS "eligible_account",
       GROUP_CONCAT(CASE WHEN config_name="Block_intl_trans" THEN config_value END) AS "Block_intl_trans"
 FROM TableA
 GROUP BY transid) V
GROUP BY KycEligible, payment_fee, eligible_account, Block_intl_trans;

Answer 3

使用 Max 进行简单查询，
结果计数可以基于您的输入数据 (transid=5, config=Block_intl_trans, value=false or value=true)

SELECT KycEligible, payment_fee, eligible_account, Block_intl_trans, COUNT(*) FROM
( 
SELECT 
       transid,
       max(CASE WHEN config_name="KycEligible" THEN value END) AS "KycEligible",
       max(CASE WHEN config_name="payment_fee" THEN value END) AS "payment_fee",
       max(CASE WHEN config_name="eligible_account" THEN value END) AS "eligible_account",
       max(CASE WHEN config_name="Block_intl_trans" THEN value END) AS "Block_intl_trans"
 FROM <YOUR_TABLE_NAME>
 GROUP BY transid
 ) tmp
GROUP BY KycEligible, payment_fee, eligible_account, Block_intl_trans;

查询以显示不同的组合，然后显示每个不同组合的计数

Query to display distinct combination and then display count for each distinct combination

mysql

join

group-by

aggregate

distinct