Sequelize ORM：在 and 运算符中创建一个 OR 运算符

Question

我正在尝试在 Sequelize 中生成此查询：

SELECT * FROM messages
WHERE (to_user_id = 1 AND from_user_id = 2)
OR (to_user_id = 2 AND from_user_id = 1)
ORDER BY "createdAt"

我这样试试：

const messages: Messages[] = await this.messages.findAll({
      where: {
        [Op.or]: [
          {
            [Op.and]: [{ to_user_id: toUserId }, { from_user_id: fromUserId }],
            [Op.and]: [{ to_user_id: fromUserId }, { from_user_id: toUserId }]
          }
        ]
      },
      attributes: {
        exclude: ['deletedAt']
      }
});

但是正在查询：

SELECT "id", "from_user_id", "to_user_id", "body", "createdAt", "updatedAt" FROM "messages" AS "messages" WHERE ("messages"."deletedAt" IS NULL AND (("messages"."to_user_id" = 2 AND "messages"."from_user_id" = 1)))

为什么我的 OR 运算符没有被应用到这两个 and 运算符中？

Answer 1

您应该为 AND 条件使用单独的对象，如下所示：

const messages: Messages[] = await this.messages.findAll({
      where: {
        [Op.or]: [
          {
            [Op.and]: [{ to_user_id: toUserId }, { from_user_id: fromUserId }]
          },
          }
            [Op.and]: [{ to_user_id: fromUserId }, { from_user_id: toUserId }]
          }
        ]
      },
      attributes: {
        exclude: ['deletedAt']
      }
});

Sequelize ORM：在 and 运算符中创建一个 OR 运算符

Sequelize ORM: Make a OR operator inside and operators

sequelize.js