在matlab中通过一组dicom图像的中线
Mid line through a set of dicom images in matlab
我在 matlab 上有一组 Dicom 图像,我想添加一条穿过所有图像的中线
我正在通过 imshow3d 函数输出图像
谢谢
编辑:这是我所拥有的,随机点不在中间,它们只是 运行 通过图像
>> clc;
>>clear;
>>%imports dicom images
>>run DicomImport.m;
>>%random points for shortest distance test
>>a = [1 10 200];
>>b = [500 512 300];
>>ab = b - a;
>>n = max(abs(ab)) + 1;
>>s = repmat(linspace(0, 1, n)', 1, 3);
>>for d = 1:3
>> s(:, d) = s(:, d) * ab(d) + a(d);
>>end
>>s = round(s);
>>Z = 593;
>>N = 512;
>>X = zeros(N, N, Z);
>>X(sub2ind(size(X), s(:, 1), s(:, 2), s(:, 3))) = 1;
>>C = find(X);
>>ans.Img(C) = 5000;
>> %shows image
>>imshow3D(ans.Img);
此代码与我为您之前的一个问题提供的答案非常相似;即我不使用 imshow3D
但框架相似且更易于修改以满足您的需要。在这种情况下,按下按钮后,堆栈的中间会出现一条线,您可以使用滑块滚动它。希望对您有所帮助。
function LineDicom(~)
clc
clear
close all
%// Load demo data
S = load('mri');
%// Get dimensions and number of slices.
ImageHeight = S.siz(1); %// Not used here
ImageWidth = S.siz(2); %// Not used here
NumSlices = S.siz(3);
S.D = squeeze(S.D);
%// Create GUI
hFig = figure('Position',[100 100 400 400],'Units','normalized');
%// create axes with handle
handles.axes1 = axes('Position', [0.2 0.2 0.6 0.6]);
%// create y slider with handle
handles.y_slider = uicontrol('style', 'Slider', 'Min', 1, 'Max', NumSlices, 'Value',1, 'Units','normalized','position', [0.08 0.2 0.08 0.6], 'callback', @(s,e) UpdateY);
handles.SlideryListener = addlistener(handles.y_slider,'Value','PostSet',@(s,e) YListenerCallBack);
%// Create pusbutton to draw line
handles.DrawLineButton= uicontrol('style', 'push','position', [40 40 100 30],'String','Draw line', 'callback', {@DrawLine,handles});
%// Flag to know whether pushbutton has been pushed
handles.LineDrawn = false;
%// Show 1st slice
imshow(S.D(:,:,1))
guidata(hFig,handles);
%// Listeners callbacks followed by sliders callbacks. Used to display each
%// slice smoothly.
function YListenerCallBack
handles = guidata(hFig);
%// Get current slice
CurrentSlice = round(get(handles.y_slider,'value'));
hold on
imshow(S.D(:,:,CurrentSlice));
%// If button was button, draw line
if handles.LineDrawn
line([round(ImageWidth/2) round(ImageWidth/2)],[1 ImageHeight],'Color','r','LineWidth',2);
end
drawnow
guidata(hFig,handles);
end
function UpdateY(~)
handles = guidata(hFig); %// Get handles.
CurrentSlice = round(get(handles.y_slider,'value'));
hold on
imshow(S.D(:,:,CurrentSlice));
if handles.LineDrawn
line([round(ImageWidth/2) round(ImageWidth/2)],[1 ImageHeight],'Color','r','LineWidth',2);
end
drawnow
guidata(hFig,handles);
end
%// Pushbutton callback to draw line.
function DrawLine(~,~,handles)
line([round(ImageWidth/2) round(ImageWidth/2)],[1 ImageHeight],'Color','r','LineWidth',2);
handles.LineDrawn = true;
guidata(hFig,handles);
end
end
示例输出:
向上移动滑块后:
这是你的意思吗?如果不是,我会删除那个答案哈哈,抱歉。
看起来 ans.Img
包含由图像堆栈组成的 3D 矩阵。看起来你有一些进展,但请允许我以不同的方式来做这件事。基本上,您需要生成一组坐标,我们可以在其中访问图像堆栈,并在图像堆栈中的每个图像的中间绘制一条垂直线。做这样的事情。首先获取堆栈的尺寸,然后确定列的中间点。接下来,生成一组坐标,为一幅图像在中间画一条线。执行此操作后,对其余切片重复此操作并获取这些的列主要索引:
%// Get dimensions
[rows,cols,slices] = size(ans.Img);
%// Get halfway point for columns
col_half = floor(cols/2);
%// Generate coordinates for vertical line for one slice
coords_middle_row = (1:rows).';
coords_middle_col = repmat(col_half, rows, 1);
%// Generate column major indices for the rest of the slices:
ind = sub2ind(size(ans.Img), repmat(coords_middle_row, slices, 1), ...
repmat(coords_middle_col, slices, 1), ...
reshape(kron(1:slices, ones(rows, 1)), [], 1));
%// Set the pixels accordingly
ans.Img(ind) = 5000;
我在 matlab 上有一组 Dicom 图像,我想添加一条穿过所有图像的中线 我正在通过 imshow3d 函数输出图像
谢谢
编辑:这是我所拥有的,随机点不在中间,它们只是 运行 通过图像
>> clc;
>>clear;
>>%imports dicom images
>>run DicomImport.m;
>>%random points for shortest distance test
>>a = [1 10 200];
>>b = [500 512 300];
>>ab = b - a;
>>n = max(abs(ab)) + 1;
>>s = repmat(linspace(0, 1, n)', 1, 3);
>>for d = 1:3
>> s(:, d) = s(:, d) * ab(d) + a(d);
>>end
>>s = round(s);
>>Z = 593;
>>N = 512;
>>X = zeros(N, N, Z);
>>X(sub2ind(size(X), s(:, 1), s(:, 2), s(:, 3))) = 1;
>>C = find(X);
>>ans.Img(C) = 5000;
>> %shows image
>>imshow3D(ans.Img);
此代码与我为您之前的一个问题提供的答案非常相似;即我不使用 imshow3D
但框架相似且更易于修改以满足您的需要。在这种情况下,按下按钮后,堆栈的中间会出现一条线,您可以使用滑块滚动它。希望对您有所帮助。
function LineDicom(~)
clc
clear
close all
%// Load demo data
S = load('mri');
%// Get dimensions and number of slices.
ImageHeight = S.siz(1); %// Not used here
ImageWidth = S.siz(2); %// Not used here
NumSlices = S.siz(3);
S.D = squeeze(S.D);
%// Create GUI
hFig = figure('Position',[100 100 400 400],'Units','normalized');
%// create axes with handle
handles.axes1 = axes('Position', [0.2 0.2 0.6 0.6]);
%// create y slider with handle
handles.y_slider = uicontrol('style', 'Slider', 'Min', 1, 'Max', NumSlices, 'Value',1, 'Units','normalized','position', [0.08 0.2 0.08 0.6], 'callback', @(s,e) UpdateY);
handles.SlideryListener = addlistener(handles.y_slider,'Value','PostSet',@(s,e) YListenerCallBack);
%// Create pusbutton to draw line
handles.DrawLineButton= uicontrol('style', 'push','position', [40 40 100 30],'String','Draw line', 'callback', {@DrawLine,handles});
%// Flag to know whether pushbutton has been pushed
handles.LineDrawn = false;
%// Show 1st slice
imshow(S.D(:,:,1))
guidata(hFig,handles);
%// Listeners callbacks followed by sliders callbacks. Used to display each
%// slice smoothly.
function YListenerCallBack
handles = guidata(hFig);
%// Get current slice
CurrentSlice = round(get(handles.y_slider,'value'));
hold on
imshow(S.D(:,:,CurrentSlice));
%// If button was button, draw line
if handles.LineDrawn
line([round(ImageWidth/2) round(ImageWidth/2)],[1 ImageHeight],'Color','r','LineWidth',2);
end
drawnow
guidata(hFig,handles);
end
function UpdateY(~)
handles = guidata(hFig); %// Get handles.
CurrentSlice = round(get(handles.y_slider,'value'));
hold on
imshow(S.D(:,:,CurrentSlice));
if handles.LineDrawn
line([round(ImageWidth/2) round(ImageWidth/2)],[1 ImageHeight],'Color','r','LineWidth',2);
end
drawnow
guidata(hFig,handles);
end
%// Pushbutton callback to draw line.
function DrawLine(~,~,handles)
line([round(ImageWidth/2) round(ImageWidth/2)],[1 ImageHeight],'Color','r','LineWidth',2);
handles.LineDrawn = true;
guidata(hFig,handles);
end
end
示例输出:
向上移动滑块后:
这是你的意思吗?如果不是,我会删除那个答案哈哈,抱歉。
看起来 ans.Img
包含由图像堆栈组成的 3D 矩阵。看起来你有一些进展,但请允许我以不同的方式来做这件事。基本上,您需要生成一组坐标,我们可以在其中访问图像堆栈,并在图像堆栈中的每个图像的中间绘制一条垂直线。做这样的事情。首先获取堆栈的尺寸,然后确定列的中间点。接下来,生成一组坐标,为一幅图像在中间画一条线。执行此操作后,对其余切片重复此操作并获取这些的列主要索引:
%// Get dimensions
[rows,cols,slices] = size(ans.Img);
%// Get halfway point for columns
col_half = floor(cols/2);
%// Generate coordinates for vertical line for one slice
coords_middle_row = (1:rows).';
coords_middle_col = repmat(col_half, rows, 1);
%// Generate column major indices for the rest of the slices:
ind = sub2ind(size(ans.Img), repmat(coords_middle_row, slices, 1), ...
repmat(coords_middle_col, slices, 1), ...
reshape(kron(1:slices, ones(rows, 1)), [], 1));
%// Set the pixels accordingly
ans.Img(ind) = 5000;