为什么在 python 中的这个二进制搜索代码中计数器没有增加?
Why is the counter not increasing in this binary search code in python?
def binary_search(array,key,left,right):
if left>right:
return -1
mid=(right+left)//2
if key==array[mid]:
return mid
i=0
if key<array[mid]:
i+=1
print("subarray at step {} : {}".format(i,array[left:mid]))
return binary_search(array,key,left,mid-1)
elif key>array[mid]:
i+=1
print("subarray at step {} : {}".format(i,array[mid:right]))
return binary_search(array,key,mid+1,right)
array=[1,2,3,4,5,6,7,8,9,11,22,33,44,55,66,77,88,99,222,333]
res= binary_search(array,88,0,len(array))
print(res if res!=-1 else "Not found")
在这个二进制搜索代码中,我无法弄清楚为什么计数器不工作。每次 i
打印出 1。计数器不增加。我究竟做错了什么?
谢谢。
i 被打印为 1 因为你是 i 在每次调用时在 binary_search 函数中被设置为 0。尝试将 i 的初始化移到函数外。
def binary_search(array,key,left,right):
global i
if left>right:
return -1
mid=(right+left)//2
if key==array[mid]:
return mid
# i=0
if key<array[mid]:
i+=1
print("subarray at step {} : {}".format(i,array[left:mid]))
return binary_search(array,key,left,mid-1)
elif key>array[mid]:
i+=1
print("subarray at step {} : {}".format(i,array[mid:right]))
return binary_search(array,key,mid+1,right)
i =0
array=[1,2,3,4,5,6,7,8,9,11,22,33,44,55,66,77,88,99,222,333]
res= binary_search(array,88,0,len(array))
您需要更改变量 i 的范围以使其成为全局变量。
将i设为全局变量并赋值变量调用global关键字
i = 0
def binary_search(array,key,left,right):
if left>right:
return -1
mid=(right+left)//2
# i=0
if key==array[mid]:
return f'it found position {mid}'
if key<array[mid]:
global i
i = i+1
print("subarray at step {} : {}".format(i,array[left:mid]))
return binary_search(array,key,left,mid-1)
elif key>array[mid]:
i+=1
print("subarray at step {} : {}".format(i,array[mid:right]))
return binary_search(array,key,mid+1,right)
array=[1,2,3,4,5,6,7,8,9,11,22,33,44,55,66,77,88,99,222,333]
res= binary_search(array,88,0,len(array))
print(len(array))
print(res if res!=-1 else "Not found")
def binary_search(array,key,left,right):
if left>right:
return -1
mid=(right+left)//2
if key==array[mid]:
return mid
i=0
if key<array[mid]:
i+=1
print("subarray at step {} : {}".format(i,array[left:mid]))
return binary_search(array,key,left,mid-1)
elif key>array[mid]:
i+=1
print("subarray at step {} : {}".format(i,array[mid:right]))
return binary_search(array,key,mid+1,right)
array=[1,2,3,4,5,6,7,8,9,11,22,33,44,55,66,77,88,99,222,333]
res= binary_search(array,88,0,len(array))
print(res if res!=-1 else "Not found")
在这个二进制搜索代码中,我无法弄清楚为什么计数器不工作。每次 i
打印出 1。计数器不增加。我究竟做错了什么?
谢谢。
i 被打印为 1 因为你是 i 在每次调用时在 binary_search 函数中被设置为 0。尝试将 i 的初始化移到函数外。
def binary_search(array,key,left,right):
global i
if left>right:
return -1
mid=(right+left)//2
if key==array[mid]:
return mid
# i=0
if key<array[mid]:
i+=1
print("subarray at step {} : {}".format(i,array[left:mid]))
return binary_search(array,key,left,mid-1)
elif key>array[mid]:
i+=1
print("subarray at step {} : {}".format(i,array[mid:right]))
return binary_search(array,key,mid+1,right)
i =0
array=[1,2,3,4,5,6,7,8,9,11,22,33,44,55,66,77,88,99,222,333]
res= binary_search(array,88,0,len(array))
您需要更改变量 i 的范围以使其成为全局变量。
将i设为全局变量并赋值变量调用global关键字
i = 0
def binary_search(array,key,left,right):
if left>right:
return -1
mid=(right+left)//2
# i=0
if key==array[mid]:
return f'it found position {mid}'
if key<array[mid]:
global i
i = i+1
print("subarray at step {} : {}".format(i,array[left:mid]))
return binary_search(array,key,left,mid-1)
elif key>array[mid]:
i+=1
print("subarray at step {} : {}".format(i,array[mid:right]))
return binary_search(array,key,mid+1,right)
array=[1,2,3,4,5,6,7,8,9,11,22,33,44,55,66,77,88,99,222,333]
res= binary_search(array,88,0,len(array))
print(len(array))
print(res if res!=-1 else "Not found")