完成 500 INTERNAL_SERVER_ERROR SpringBoot Angular : OneToMany 问题

Question

每一次我尝试加载列表 RDV 我都遇到了这个问题:

**类型定义错误：[简单类型，classorg.hibernate.proxy.pojo.bytebuddy.ByteBuddyInterceptor]；嵌套异常是 com.fasterxml.jackson.databind.exc.InvalidDefinitionException：没有找到 class org.hibernate.proxy.pojo.bytebuddy.ByteBuddyInterceptor 的序列化器，也没有发现创建 BeanSerializer 的属性（为避免异常，禁用 SerializationFeature.FAIL_ON_EMPTY_BEANS）（通过引用链：java.util.ArrayList[0]->com.angular.springboot.model.Rv["client"]->com.angular.springboot.model.Client$HibernateProxy$3lai3IqI["hibernateLazyInitializer"])]

o.s.web.servlet.DispatcherServlet：完成 500 INTERNAL_SERVER_ERROR**

但是当我删除 OneToMany 它的工作!!

这是我的客户 class :

public class Client implements Serializable {

@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private Long        id;
private String      name;
private String      prenom;

@JsonIgnoreProperties({ "hibernateLazyInitializer", "handler" })
@OneToMany(mappedBy = "client", fetch = FetchType.LAZY)
private List<Rv>    lrdvs;

@JsonIgnore
public List<Rv> getLrdvs() {
    return lrdvs;
}

@JsonIgnore
public void setLrdvs(List<Rv> lrdvs) {
    this.lrdvs = lrdvs;
}

}

这是 Medecin class:

 @Entity
@Data
@AllArgsConstructor
@NoArgsConstructor
@Table(name = "medecins")
public class Medecin implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private long        id;
private String      nom;
private String      prenom;
private String      specialite;
@JsonIgnoreProperties({ "hibernateLazyInitializer", "handler" })
@OneToMany(mappedBy = "medecin", fetch = FetchType.LAZY)
private List<Rv>    lrdvs;

@JsonIgnore
public List<Rv> getLrdvs() {
    return lrdvs;
}

@JsonIgnore
public void setLrdvs(List<Rv> lrdvs) {
    this.lrdvs = lrdvs;
}

}

这是我的 RDV class

@Entity
@Data
@AllArgsConstructor
public class Rv {
@Id
@GeneratedValue(strategy = GenerationType.AUTO)
private long        id;
@DateTimeFormat(pattern = "yyyy-MM-dd")
private LocalDate   jour;

@JoinColumn(name = "ID_Client")
@ManyToOne(fetch = FetchType.LAZY, optional = false)
private Client      client;

@JoinColumn(name = "ID_Medecin")
@ManyToOne(fetch = FetchType.LAZY, optional = false)
private Medecin     medecin;

public Rv() {
    client = new Client();
    medecin = new Medecin();
}

}

谁知道怎么解决。谢谢 :)

Answer 1

将此行添加到您的应用程序属性

spring.jackson.serialization.fail-on-empty-beans=false

完成 500 INTERNAL_SERVER_ERROR SpringBoot Angular : OneToMany 问题

Completed 500 INTERNAL_SERVER_ERROR SpringBoot Angular : OneToMany Problem

spring-data

spring-data-jpa

angularjs

spring-boot

angular