不了解如何在 ViewController 之间传递值

Question

我已经知道如何在 UIViewController 之间传递值或变量。事实上，我在 2 + 2 UIViewController 之间有 2 个转换，它们工作正常，但我有一个不这样做。

我已经尝试复制所有内容，但这个似乎不起作用。

这就是我处理点击以传递给另一个人的方式 UIViewController:

-(void)launchProfile:(int) option {
    UIStoryboard *sb = [UIStoryboard storyboardWithName:@"Profile" bundle:nil];
    ProfileControllerViewController *vc = [sb instantiateViewControllerWithIdentifier:@"ProfileControllerViewController"];

    [vc passValue:_user];
    [vc passOption:option];
    vc.modalTransitionStyle = UIModalTransitionStyleFlipHorizontal;
    [self presentViewController:vc animated:YES completion:NULL];
}

这是我的 ProfileControllerViewController.h:

@interface ProfileControllerViewController : UIViewController

-(void)passValue:(NSDictionary*)user;
-(void)passOption:(int)option;

@property (nonatomic , strong) NSDictionary* user;

// ...

@end

This is myProfileControllerViewController.m`（我实现函数的部分

@implementation ProfileControllerViewController

int optionSelected = -1;
const int optionChanges = 0;
const int optionComments = 1;

-(void)passOption:(int) option {
    optionSelected = option;
}

- (void) passValue:(NSDictionary *)user_ {
    _user = user_;
}

// ...

@end

当它执行 passValue 或 passOption 时，错误是：

2015-06-27 12:31:51.616 Ch4nge.me[41958:1907763] viewDidAppear 2015-06-27 12:31:56.041 Ch4nge.me[41958:1907763] Unknown class _TtC31ProfileControllerViewController31ProfileControllerViewController in Interface Builder file. 2015-06-27 12:31:57.102 Ch4nge.me[41958:1907763] -[UIViewController passUser:]: unrecognized selector sent to instance 0x7fb505412c00 2015-06-27 12:31:57.107 Ch4nge.me[41958:1907763] *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '-[UIViewController passUser:]: unrecognized selector sent to instance 0x7fb505412c00'

有什么问题吗？？？

非常感谢您。

Answer 1

-[UIViewController passUser:]: unrecognized selector sent to instance 表示您的 vc 变量不是 ProfileControllerViewController 类型。

可能您没有在 XIB 或 Storyboard 中设置 class，这就是 instantiateViewControllerWithIdentifier 没有返回预期类型的原因；而是返回类型 UIViewController.

的默认实例

Answer 2

你可以使用另一个选项来解决这个错误，你可以使用 segue，

参考下面link，

How to Send data between view controllers StoryBoard Xcode

Answer 3

您可以使用：

-(void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender

{

   if([segue.identifier isEqualToString:@"segueIdentifer"]) //use whatever identifer you have set 

   {

      ProfileControllerViewController *vc = (ProfileControllerViewController *)segue.destinationViewController;

      vc.user = dict; //NSDictionary value

      vc.option = 1; //Use whatever integer you want to pass

   }

}

并在您的 ProfileControllerViewController.h 中定义 @property (nonatomic, strong) NSDictionary* user; 和 @property (nonatomic, assign) int option;

不了解如何在 ViewController 之间传递值

Not understanding how to pass values between ViewControllers

objective-c

uiviewcontroller

ios