SQL 根据 like 语句和 Group by 进行计数

Question

我有一个 table 类似于下面的结构。我需要根据 MessageValue 列的值计算失败、成功和部分成功的次数。如果 Messagevale 列包含 'failed' 那么它是失败的，'success' 被认为是成功而 'partial success' 被认为是部分失败。所以我需要在计数中检查 LIKE 标准，而且我需要它基于日期。我尝试使用 Count 和 Group by ，但没有得到我需要的东西。

Date                   MessageValue
-----------------------------------------------
10/18/2020             Process failed some text here
10/18/2020             Process success some text here
10/19/2020             Partial success some text here
10/19/2020             Process failed some text here
10/19/2020             Process failed some text here
10/19/2020             Process partial success some text here
10/20/2020             Process partial success some text here
------------------------------------------------

所以输出应该如下所示。

Date                   Success      Failure     Partial Failure
-----------------------------------------------------------------
10/18/2020               1             1            0
10/19/2020               1             2            1
10/20/2020               0             0            1

Answer 1

您可以在 like 条件下进行条件聚合。这似乎可以满足您的要求：

select
    date,
    sum(case when col like '%success%' and col not like '%partial success%' then 1 else 0 end) success,
    sum(case when col like '%failed%' then 1 else 0 end) failure,
    sum(case when col like '%partial failed%' then 1 else 0 end) partial_success
from mytable
group by date

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