Swift2 - HKSampleQuery

Question

let hkSampleType:HKSampleType = HKSampleType.correlationTypeForIdentifier(HKCorrelationTypeIdentifierFood)!
let query = HKSampleQuery(sampleType: hkSampleType, predicate: predicate, limit: 80, sortDescriptors: nil, resultsHandler: { (query:HKSampleQuery, results:[HKSample]!, error:NSError!) -> Void in
    //code
})

就是这样，但我收到错误消息：Cannot find an initializer for type 'HKSampleQuery' that accepts an argument list of type '(sampleType: HKSampleType, predicate: NSPredicate, limit: Int, sortDescriptors: nil, resultsHandler: (HKSampleQuery, [HKSample]!, NSError!) -> Void)'

正确的语法是怎样的？

Answer 1

我不是 Swift 或 HealthKit 方面的专家，但这编译在 Xcode 7:

let hkSampleType:HKSampleType = HKSampleType.correlationTypeForIdentifier(HKCorrelationTypeIdentifierFood)!
let query = HKSampleQuery(sampleType: hkSampleType, predicate: nil, limit: 80, sortDescriptors: nil, resultsHandler: { (query:HKSampleQuery, results:[HKSample]?, error:NSError?) -> Void in
    //code
})

在闭包中，results 和 error 是 iOS 中的可选项 9. 你将它们声明为展开的。

我不确定的一件事是您可以将 HKSampleQuery 用于 HKCorrelation。这是 HKCorrelationQuery 的正确声明，以备不时之需：

let corralationType = HKCorrelationType.correlationTypeForIdentifier(HKCorrelationTypeIdentifierFood)!
let query = HKCorrelationQuery(type: corralationType, predicate: nil, samplePredicates: nil) { (query: HKCorrelationQuery, results: [HKCorrelation]?, error: NSError?) -> Void in

}