python 中的 Antlr 4 未按预期工作(尝试解析一本书的章节和段落)

Antlr 4 in python not working as expected (trying to parse chapter and paragraph of a book)

我想创建一个非常简单的 ANTLR4 解析器(在 Python 中),没有侦听器和访问器,它以任何顺序将一本书的章节和段落作为输入,returns high_level(章节)和 low_level(段落)的条目,例如如果我输入 2 aa 2,它应该打印“第 2 章,段落 a”。

这是我的Example.g4

grammar Example;

text
    : paragraph ;

paragraph
    : high_level (WS low_level)?
    | low_level WS high_level
    ;

low_level
    : 'a' | 'b'  | 'c'  ;

high_level
    : '1'  | '2'  | '3';
WS : [ \t\r\n]+ ;

我在我的终端上这样做 java -jar ~/antlr-4.8-complete.jar -Dlanguage=Python3 -no-listener -no-visitor Example.g4

生成两个python文件,然后我写了下面的python脚本

from antlr4 import *
from ExampleLexer import ExampleLexer
from ExampleParser import ExampleParser


def main():
    while True:
        text = InputStream(input(">"))
        lexer = ExampleLexer(text)
        stream = CommonTokenStream(lexer)
        parser = ExampleParser(stream)
        tree = parser.text()
        query = tree.paragraph()
        low_level = query.low_level()
        high_level = query.high_level()
        print(f"chapter {high_level}, paragraph {low_level}")


if __name__ == '__main__':
    main()

但是,如果我然后 运行 它并输入 2 a,我得到这个 chapter [10 8], paragraph [12 8]

谁能解释一下我做错了什么?我不明白方括号中的数字。

它只是 RuleContext 显示的一些调试信息(您生成的 Low_levelContextHigh_levelContext 类 从中扩展)。在您的情况下,显示规则的 invokingStateparentCtx

查看源代码:

class RuleContext(RuleNode):

    ...

    def __str__(self):
        return self.toString(None, None)

    ...

    def toString(self, ruleNames:list, stop:RuleContext)->str:
        with StringIO() as buf:
            p = self
            buf.write("[")
            while p is not None and p is not stop:
                if ruleNames is None:
                    if not p.isEmpty():
                        buf.write(str(p.invokingState))
                else:
                    ri = p.getRuleIndex()
                    ruleName = ruleNames[ri] if ri >= 0 and ri < len(ruleNames) else str(ri)
                    buf.write(ruleName)

                if p.parentCtx is not None and (ruleNames is not None or not p.parentCtx.isEmpty()):
                    buf.write(" ")

                p = p.parentCtx

            buf.write("]")
            return buf.getvalue()

    ...

https://github.com/antlr/antlr4/blob/master/runtime/Python3/src/antlr4/RuleContext.py

你没有解释你想显示什么,但我猜是规则匹配的文本,在这种情况下你可以这样做:

print(f"chapter {high_level.getText()}, paragraph {low_level.getText()}")