sql 排序依据和分组汇总

Question

我的查询如下所示。输出

当前输出

Role            Cases prepped % Completed    
State Member 1  10    5       50%
State Member 2  10    7       70%
State President 10    2       20%
Summary         30    14      46.6%

预期输出

Role            Cases prepped % Completed
State President 10    2       20%
State Member 1  10    5       50%
State Member 2  10    7       70%
Summary         30    14      46%

角色table

id name
30 State President
40 State Member

这是我的查询，

SELECT COALESCE(ROLE, 'Summary') ROLE,   
       count(*) AS cases, 
       SUM(CASE WHEN PREPARED = 'Y' THEN 1
                ELSE 0
           END) AS prepped, 
 round(avg(case when prepared = 'Y' then 100 else 0 end),2)||'%' as % Completed
FROM
  (SELECT CASE
              WHEN r.id = 30 THEN r.name
              ELSE r.name || ' ' || u.case_member_id
          END AS ROLE,
          bi.prepared
   FROM cases c
   LEFT JOIN case_inventory ci ON ci.case_id = c.id
   AND c.id = ci.case_id
   AND c.delete_date IS NULL
   AND ci.case_id =40
  Left JOIN users u ON ci.assigned_to = u.id
   Left JOIN ROLES r ON u.role_id = r.id
   Left JOIN user_cases_map uc ON c.id = uc.case_id
   AND uc.id = 1572919346)
GROUP BY ROLLUP (ROLE);

我现在想根据角色对行进行排序。第一条记录应该是州总统，然后是州议员 1. 州议员 2. 依此类推。我试图在内部子句中使用 order by 但它没有帮助。它没有任何作用。添加外部 select 也不会改变任何东西。非常感谢任何帮助。谢谢。

Answer 1

在 comp.

的表达式中目前有 sum(count(*)) 的地方仅使用 count(*)

Answer 2

从您当前的查询开始，您可以只使用 avg():

SELECT 
    COALESCE(ROLE, 'Summary') ROLE,   
    COUNT(*) AS cases, 
    SUM(CASE WHEN PREPARED = 'Y' THEN 1 ELSE 0 END) AS prepped, 
    AVG(CASE WHEN PREPARED = 'Y' THEN 1 ELSE 0 END) AS ratio_completed
FROM ...

这个 returns 一个介于 0 和 1 之间的数字。如果您喜欢百分比（介于 0 和 100 之间），可以将 THEN 1 替换为 THEN 100。

Answer 3

在 SQL 中将更复杂的逻辑拆分为多个子查询是一个很好的做法。

我建议使用一个子查询（基本上是您的查询）来计算计数，并另一个子查询来计算比率。

新的主要查询是

select ROLE, CASES, PREPPED,
(PREPPED/nullif(CASES,0))* 100 proc_completed
from (your query);

ROLE                 CASES    PREPPED PROC_COMPLETED
--------------- ---------- ---------- --------------
State President         10          2             20
State Member 1          10          5             50
State Member 2          10          7             70
State Member 2           0          0               
Summary                 10         14            140

请注意，我在 count = 0 的边缘情况下添加了一个新行，并且我使用 nullif 函数来避免出现问题。

sql 排序依据和分组汇总

sql order by with group by rollup

sql

oracle

oracle11g