如何在列表的嵌套字典中获取键的最大值

Question

我想通过在其键中搜索值来打印具有键及其最大值的字典。

Input
dict_1 = {
    0: [1], 
    1: [2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 16, 18], 
    12: [13, 14, 15], 
    14: [37],
    16: [17], 
    18: [19], 
    19: [20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 37, 45], 
    29: [30, 31, 32, 33, 34, 35, 36], 
    37: [38, 39, 40, 41, 42], 
    42: [43, 44], 
    45: [46]
}

Expected Output
dict_2 = {0: 46, 1: 46, 12: 44, 14:44, 16: 17, 18: 46, 19: 46, 29: 36, 37: 44, 42: 44, 45: 46}

例如，键 0 的值为 1，该值是我字典的第二个键，该键的值为 18，这也是字典中的键，该键 18 的值 19 又是具有最大值的键为 45，它也是一个值为 46 的键，因此键 0 的最大值为 46

Answer 1

dict_1 = {0: [1], 
1: [2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 16, 18], 
12: [13, 14, 15], 
14: [37],
16: [17], 
18: [19], 
19: [20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 37, 45], 
29: [30, 31, 32, 33, 34, 35, 36], 
37: [38, 39, 40, 41, 42], 
42: [43, 44], 
45: [46]}

d={}

for key,value in dict_1.items():
    val=[i for i in value if i in dict_1]
    if val:
        val=max(val)
        while val in dict_1:
            val=max(dict_1[val])
        new_val=val
    else:
        new_val=max(value)
    d[key]=new_val

print(d) # {0: 46, 1: 46, 12: 44, 14: 44, 16: 17, 18: 46, 19: 46, 29: 36, 37: 44, 42: 44, 45: 46}

Answer 2

dict_1 = {

0: [1],
1: [2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 16, 18],
12: [13, 14, 15],
14: [37],
16: [17],
18: [19],
19: [20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 37, 45],
29: [30, 31, 32, 33, 34, 35, 36],
37: [38, 39, 40, 41, 42],
42: [43, 44],
45: [46]

}

def maxv(d, k):

if k not in d.keys():
    return k
else:
    m = max(d[k])
    return maxv(d, m)

def create_dict(dic):

d = {}
for key in dic.keys():
    d[key] = maxv(dic, key)
return d

打印(create_dict(dict_1))

如何在列表的嵌套字典中获取键的最大值

How to get the max value for key in nested dictionary of list

python

python-2.7

python-3.x