为什么 sequelize 忽略引用属性？

Question

我正在使用续集：

 "dependencies": {
    "@types/node": "^14.14.6",
    "sequelize": "^6.3.5",
    "tedious": "^9.2.1",
    "typescript": "^4.0.5"
  }

我的 sql 数据库中有两个 table：user 和 task。

task_user_id in task table 引用了用户 table:

taskUserId: {
    type: DataTypes.UUID,
    allowNull: true,
    references: {
     model: "user",
     key: "id",
    },
    field: "task_user_id",
},

那么，为什么当我使用运行 findAll 函数时，我没有在我正在获取的对象中获取用户详细信息？

const u = await Task.findAll({ raw: true });

我的代码中可能缺少某些内容？

task.ts:

/* jshint indent: 2 */

import { DataTypes, Model, Sequelize } from "sequelize";

export interface TaskAttributes {
  id?: number;
  taskUserId?: string;
  name?: string;
}

export class Task
  extends Model<TaskAttributes, TaskAttributes>
  implements TaskAttributes {
  id?: number;
  taskUserId?: string;
  name?: string;

  static initModel(sequelize: Sequelize) {
    Task.init(
      {
        id: {
          autoIncrement: true,
          type: DataTypes.INTEGER,
          allowNull: false,
          primaryKey: true,
        },
        taskUserId: {
          type: DataTypes.UUID,
          allowNull: true,
          references: {
            model: "user",
            key: "id",
          },
          field: "task_user_id",
        },
        name: {
          type: DataTypes.STRING(600),
          allowNull: true,
          field: "task_name",
        },
      },
      {
        sequelize,
        tableName: "task",
        schema: "dbo",
        timestamps: false,
      }
    );
    return Task;
  }
}

user.ts:

/* jshint indent: 2 */

import { DataTypes, Model, Sequelize } from 'sequelize';

export interface UserAttributes {
  id?: string;
  name?: string;
  email?: string;
  password?: string;
}

export class User extends Model<UserAttributes, UserAttributes> implements UserAttributes {
  id?: string;
  name?: string;
  email?: string;
  password?: string;

  static initModel(sequelize: Sequelize) {
    User.init(
      {
        id: {
          type: DataTypes.UUID,
          allowNull: false,
          primaryKey: true,
        },
        name: {
          type: DataTypes.STRING(80),
          allowNull: false,
        },
        email: {
          type: DataTypes.STRING(255),
          allowNull: false,
        },
        password: {
          type: DataTypes.STRING,
          allowNull: false,
        },
      },
      {
        sequelize,
        tableName: 'user',
        schema: 'dbo',
        timestamps: false,
      }
    );
    return User;
  }
}

Answer 1

为了请求具有链接模型的模型，您应该像这样在模型之间添加显式关联：

Task.belongTo(User, { foreignKey: 'task_user_id' })

之后，您可以像这样与链接用户一起查询任务：

const u = await Task.findAll({ raw: true, include: [User] });

为什么 sequelize 忽略引用属性？

Why sequelize ignore the references property?

javascript

node.js

sequelize.js

为什么 sequelize 忽略引用 属性？

Why sequelize ignore the references property?

javascript

node.js

sequelize.js

为什么 sequelize 忽略引用属性？