使用具有参数化类型的特征的意外模式匹配行为
Unexpected pattern matching behaviour using a trait with parameterized types
我在 scala 2.12.9 中看到以下行为:
case class A()
case class B()
trait X {
type T
def handle: PartialFunction[Any, Unit] = {
case in: T =>
println(s"is a T, $in")
case m =>
print(s"not a T, $m")
}
}
class X1 extends X {
override type T = A
}
object Cast extends App {
val x1 = new X1()
x1.handle(B())
}
输出是是一个T,B()。我希望它“不是 T”,因为我已经将 X 的类型参数覆盖为 A。我错过了什么?
更新:
我不知道类型成员(不仅仅是类型参数)也会受到类型擦除的影响。谢谢你们! @DmytroMitin 的解决方法非常有效。
这是因为类型擦除。
编译时出现警告
abstract type pattern X.this.T is unchecked since it is eliminated by erasure
尝试
import shapeless.TypeCase
trait X {
type T
val OfTypeT: TypeCase[T] // abstract val, not def
def handle: PartialFunction[Any, Unit] = {
case OfTypeT(in) =>
println(s"is a T, $in")
case m =>
print(s"not a T, $m")
}
}
class X1 extends X {
override type T = A
override val OfTypeT = TypeCase[A]
}
val x1 = new X1()
x1.handle(B()) // not a T, B()
请参阅在 Scala 中模式匹配泛型类型的方法 https://gist.github.com/jkpl/5279ee05cca8cc1ec452fc26ace5b68b (another copy of a blog post: http://web.archive.org/web/20171013214913/http://www.cakesolutions.net/teamblogs/ways-to-pattern-match-generic-types-in-scala)
如果 T
是类型参数而不是类型成员,我们可以使用上下文绑定而不是覆盖
import shapeless.{TypeCase, Typeable}
abstract class X[T: Typeable] {
private val OfTypeT = TypeCase[T]
def handle: PartialFunction[Any, Unit] = {
case OfTypeT(in) =>
println(s"is a T, $in")
case m =>
print(s"not a T, $m")
}
}
class X1 extends X[A]
val x1 = new X1()
x1.handle(B()) // not a T, B()
或者我们可以使用 TypeTag
import scala.reflect.runtime.universe.{TypeTag, typeOf, Type}
def getType[T: TypeTag](t: T): Type = typeOf[T]
abstract class X[T: TypeTag] {
def handle: PartialFunction[Any, Unit] = {
case in if typeOf[T] =:= getType(in) =>
println(s"is a T, $in")
case m =>
print(s"not a T, $m")
}
}
class X1 extends X[A]
val x1 = new X1()
x1.handle(B()) // not a T, B()
或ClassTag
import scala.reflect.ClassTag
abstract class X[T: ClassTag] {
def handle: PartialFunction[Any, Unit] = {
case in: T =>
println(s"is a T, $in")
case m =>
print(s"not a T, $m")
}
}
class X1 extends X[A]
val x1 = new X1()
x1.handle(B()) // not a T, B()
我在 scala 2.12.9 中看到以下行为:
case class A()
case class B()
trait X {
type T
def handle: PartialFunction[Any, Unit] = {
case in: T =>
println(s"is a T, $in")
case m =>
print(s"not a T, $m")
}
}
class X1 extends X {
override type T = A
}
object Cast extends App {
val x1 = new X1()
x1.handle(B())
}
输出是是一个T,B()。我希望它“不是 T”,因为我已经将 X 的类型参数覆盖为 A。我错过了什么?
更新: 我不知道类型成员(不仅仅是类型参数)也会受到类型擦除的影响。谢谢你们! @DmytroMitin 的解决方法非常有效。
这是因为类型擦除。
编译时出现警告
abstract type pattern X.this.T is unchecked since it is eliminated by erasure
尝试
import shapeless.TypeCase
trait X {
type T
val OfTypeT: TypeCase[T] // abstract val, not def
def handle: PartialFunction[Any, Unit] = {
case OfTypeT(in) =>
println(s"is a T, $in")
case m =>
print(s"not a T, $m")
}
}
class X1 extends X {
override type T = A
override val OfTypeT = TypeCase[A]
}
val x1 = new X1()
x1.handle(B()) // not a T, B()
请参阅在 Scala 中模式匹配泛型类型的方法 https://gist.github.com/jkpl/5279ee05cca8cc1ec452fc26ace5b68b (another copy of a blog post: http://web.archive.org/web/20171013214913/http://www.cakesolutions.net/teamblogs/ways-to-pattern-match-generic-types-in-scala)
如果 T
是类型参数而不是类型成员,我们可以使用上下文绑定而不是覆盖
import shapeless.{TypeCase, Typeable}
abstract class X[T: Typeable] {
private val OfTypeT = TypeCase[T]
def handle: PartialFunction[Any, Unit] = {
case OfTypeT(in) =>
println(s"is a T, $in")
case m =>
print(s"not a T, $m")
}
}
class X1 extends X[A]
val x1 = new X1()
x1.handle(B()) // not a T, B()
或者我们可以使用 TypeTag
import scala.reflect.runtime.universe.{TypeTag, typeOf, Type}
def getType[T: TypeTag](t: T): Type = typeOf[T]
abstract class X[T: TypeTag] {
def handle: PartialFunction[Any, Unit] = {
case in if typeOf[T] =:= getType(in) =>
println(s"is a T, $in")
case m =>
print(s"not a T, $m")
}
}
class X1 extends X[A]
val x1 = new X1()
x1.handle(B()) // not a T, B()
或ClassTag
import scala.reflect.ClassTag
abstract class X[T: ClassTag] {
def handle: PartialFunction[Any, Unit] = {
case in: T =>
println(s"is a T, $in")
case m =>
print(s"not a T, $m")
}
}
class X1 extends X[A]
val x1 = new X1()
x1.handle(B()) // not a T, B()